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anonymous
 4 years ago
Need some help identifying the increase intervals of the graph of xtanx
anonymous
 4 years ago
Need some help identifying the increase intervals of the graph of xtanx

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349987981581:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know this is a even function about the y axis, and the domain and asymptotes are pi/2,pi/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just wondering how to show the intervals of increase and decrease

Venomblast
 4 years ago
Best ResponseYou've already chosen the best response.0so 90 degrees <x<90 degrees

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0usually i take f'x and solve for 0

Venomblast
 4 years ago
Best ResponseYou've already chosen the best response.0i see no 0. is this is an equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@zepdrix hey do you think you could explain how they designate zero as a critical point?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349988599121:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0should i just know that, from the x and y intercepts and the even symetry? and a basic knowledge of the tanx graph?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because when i set my derivative = 0 i have problems

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1349988578994:dw Hmm yah this derivative does seem to be putting up a fight :\ Hmmmmm

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i tried changing everything to sines and cosines and still a mess

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1349988855254:dw Ah good call, I think that's how you find it! :) The top is a big mess, yes. But the bottom I think you can solve for a critical point.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1349988866328:dw

Venomblast
 4 years ago
Best ResponseYou've already chosen the best response.0get the common denominator. so multiply cosx on the 1st term

Venomblast
 4 years ago
Best ResponseYou've already chosen the best response.0i guess he/she got it from here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think the top should be ignored

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the book doesent have a mention of it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0neither does the graph

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0maybe it would matter if the interval was larger than pi/2,pi/2

zepdrix
 4 years ago
Best ResponseYou've already chosen the best response.1Hmmm wait what was I saying? cos x = 0 Hmm that should give you x = pi/2 right? why did i say it was x = 0? Hmmmmmmmmmmmmmmmmm Now I'm back to being confused about where the 0 critical point is coming from :D lol
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