Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

orbie

  • 3 years ago

I need a refresher on how to do this. Unfortunately I don't have my notes with me. Problem is attached.

  • This Question is Closed
  1. orbie
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  2. swissgirl
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok for starters g(2) means solve the equation when x=2 So which equation would you use when x=2?

  3. swissgirl
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @orbie R u there?

  4. orbie
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No idea is like asking that if you plug 2 into the left side of the equation, it must equal whatever is on the right side of the equation? =/

  5. swissgirl
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    well if you look at G(x) it gives you 4 equations and after each equation it says when you should use each equation. The first equation should be used when x is less than or equal to 1 The second equation should be used when x is less than 1 and when x is less than or equal to 3 which basically only includes 2 and 3 The third equation is when x is inbtwn 3 and 6 but not including 3 or 6 so this basically means when x equals 4 or 5 you use the third equation The last equation is used when x is equla to 6 or greater than 6 So which equation would we use when x=2?

  6. orbie
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the second equation \[\left| x-12 \right|\]

  7. swissgirl
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    correct So g(2) means we replace our x with 2 g(2)=|2-12| g(2)=|-10|=10 So g(2)=10

  8. orbie
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ooooh okay I understand now. Thank you!

  9. swissgirl
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Your welcome :)

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy