pokemon23
  • pokemon23
If y = 5x + 2, then find the value of 10xy + 4y in terms of y.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
pokemon23
  • pokemon23
@Hero @Calcmathlete
bahrom7893
  • bahrom7893
wow u didn't type @bah here...
bahrom7893
  • bahrom7893
I'm not smart enough????

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

bahrom7893
  • bahrom7893
y=5x+2 y-2 = 5x x = (1/5)(y-2)
bahrom7893
  • bahrom7893
10xy + 4y = 10 (1/5)(y-2) y + 4y = 2(y - 2)y + 4y = 2y^2 - 4y + 4y = 2y^2 <-Final answer
bahrom7893
  • bahrom7893
and it's you're
pokemon23
  • pokemon23
o_o I'm taking the PSAT... I don't know how to do these types of questions......
anonymous
  • anonymous
To clarify on what @bahrom7893 said, I would've done something a bit simpler? \[\implies10xy + 4y~~~~~~~~~~Original~Expression\]\[\implies 2y(5x + 2)~~~~~~~~~Factor~out~the~GCF\]\[\implies 2y(y) ~~~~~~~~~~~~~~~~~~Substitute\]\[\implies 2y^2~~~~~~~~~~~~~~~~~~~~~Multiplication~of~variables\]
pokemon23
  • pokemon23
ok let's do another problem I need to get better.
anonymous
  • anonymous
Uh ok then... \[y = (3x + 2)^3\]\[\text{Simplify in terms of y: } (9x + 6)^3\]
anonymous
  • anonymous
Very similar to the one you were doing on that PSAT question.
pokemon23
  • pokemon23
ok I think I got it.
pokemon23
  • pokemon23
so do I multiply to the 3rd power?
anonymous
  • anonymous
Yes, the \(^{'3'}\) implies cubing it or multiplying by itself 3 times.
pokemon23
  • pokemon23
9x*9x*9x?
anonymous
  • anonymous
Not quite...could you show me what you did?
pokemon23
  • pokemon23
well you its |dw:1349998059319:dw| so i multiply the exponent to the 3rd?
pokemon23
  • pokemon23
i know its wrong..
anonymous
  • anonymous
If you were to actually multiply it out, it would be like doing this: \[(9x + 6)^3 \implies (9x + 6)(9x + 6)(9x + 6)\]which is unnecessary here. Again, like previous times, do you see anything that you can factor out?
pokemon23
  • pokemon23
i keep forgetting to factor.....
pokemon23
  • pokemon23
my spectacles are deceiving me
anonymous
  • anonymous
Hmm?
pokemon23
  • pokemon23
ok if we can (9x+6) (9x+6) (9x+6)
pokemon23
  • pokemon23
what's next?
anonymous
  • anonymous
THat is not a step that we even need to take, but we can solve it using that. It would be a slightly longer process though. Let's work WITHIN the parentheses first. Don't do anything ith the \(^3\) for now.
pokemon23
  • pokemon23
ok will keep it (9x+6)^3
anonymous
  • anonymous
Now factor what's within the parentheses...
pokemon23
  • pokemon23
3(3x+2)^3
anonymous
  • anonymous
The 3 wouldn't go outside of the parentheses because it's still under the \(^3\), so it would become \((3(3x + 2))^3\) Do you see why that is?
pokemon23
  • pokemon23
explain those parentheses
anonymous
  • anonymous
Well, let's take the approach that you had before. \[(9x + 6)^3 \implies (9x + 6)(9x + 6)(9x + 6) \implies 3(3x + 2)3(3x + 2)3(3x + 2)\]\[3 \times 3 \times 3(3x + 2)(3x + 2)(3x + 2) \implies 3^3(3x + 2)^3~~~OR~~~27(3x + 2)^3\]See what I did? You can't take the 3 \(\LARGE{ENTIRELY}\) out of the parentheses unless you take the \(^3\) with it.
pokemon23
  • pokemon23
oh
anonymous
  • anonymous
\[\LARGE{┬┐Entiendes?}\]
pokemon23
  • pokemon23
si
anonymous
  • anonymous
Can you predict what to do next?
pokemon23
  • pokemon23
distributive
anonymous
  • anonymous
What? Keep in mind the original question and what y is equal to...
pokemon23
  • pokemon23
then we should substitute
anonymous
  • anonymous
\[\huge\color{red}{Y}\color{blue}{E}\color{salmon}{S}\color{green}{!}\]
pokemon23
  • pokemon23
so ....
pokemon23
  • pokemon23
instead of the x make it a y?
anonymous
  • anonymous
Uh...remember that \(y = (3x + 2)^3...\) You can substitute y in for that value now. Tell me what your final answer would be now.
pokemon23
  • pokemon23
jinkies
pokemon23
  • pokemon23
hmm ummm
pokemon23
  • pokemon23
y=27x^3+8
anonymous
  • anonymous
Umm...no... \[(9x + 6)^3 \implies (3(3x + 2))^3 \implies 3^3(3x + 2)^3 \implies 27(3x + 2)^3 \implies 27y\]
anonymous
  • anonymous
Do you see why? Do you understand what it means when it says "in terms of y"? Do you see that we're replacing ALL OF \((3x + 2)^3\) with y? That way nothing in that is cubed anymore?
pokemon23
  • pokemon23
I still don't get how divided 27(3x+2)^3 to get 27y
anonymous
  • anonymous
Where do you see a division symbol? There is no division invloved in this except the beginning factoring portion. \[\large{\text{We just clarified that y}}~\LARGE\text{=}~\large{(3x + 2)^3}\]Just replace \((3x + 2)^3\) with y and that's all that happened.
pokemon23
  • pokemon23
where does (3x+2)^3? disappear?
pokemon23
  • pokemon23
I don't understand the y part...
anonymous
  • anonymous
fdiofvejbvnweokgnweoifnerwo That is what we're substituting with y! Remember when we said y = 2 and we plugged it in? Well we could say that 2 = y and we plug y in for the 2. SAME THING HERE. y = (3x + 2)^3 (3x + 2)^3 = y Now you just plug in why for the (3x + 2)^3
anonymous
  • anonymous
You still there?
pokemon23
  • pokemon23
im here

Looking for something else?

Not the answer you are looking for? Search for more explanations.