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wow u didn't type @bah here...

I'm not smart enough????

y=5x+2
y-2 = 5x
x = (1/5)(y-2)

10xy + 4y = 10 (1/5)(y-2) y + 4y = 2(y - 2)y + 4y = 2y^2 - 4y + 4y = 2y^2 <-Final answer

and it's you're

o_o I'm taking the PSAT... I don't know how to do these types of questions......

ok let's do another problem I need to get better.

Uh ok then...
\[y = (3x + 2)^3\]\[\text{Simplify in terms of y: } (9x + 6)^3\]

Very similar to the one you were doing on that PSAT question.

ok I think I got it.

so do I multiply to the 3rd power?

Yes, the \(^{'3'}\) implies cubing it or multiplying by itself 3 times.

9x*9x*9x?

Not quite...could you show me what you did?

well you its |dw:1349998059319:dw| so i multiply the exponent to the 3rd?

i know its wrong..

i keep forgetting to factor.....

my spectacles are deceiving me

Hmm?

ok if we can (9x+6) (9x+6) (9x+6)

what's next?

ok will keep it (9x+6)^3

Now factor what's within the parentheses...

3(3x+2)^3

explain those parentheses

oh

\[\LARGE{Â¿Entiendes?}\]

si

Can you predict what to do next?

distributive

What? Keep in mind the original question and what y is equal to...

then we should substitute

\[\huge\color{red}{Y}\color{blue}{E}\color{salmon}{S}\color{green}{!}\]

so ....

instead of the x make it a y?

jinkies

hmm ummm

y=27x^3+8

I still don't get how divided 27(3x+2)^3 to get 27y

where does (3x+2)^3? disappear?

I don't understand the y part...

You still there?

im here