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j814wong
 2 years ago
Best ResponseYou've already chosen the best response.2a = Δv/Δt = (vfinal  vinitial) / (tfinal  tinitial)

sami2012
 2 years ago
Best ResponseYou've already chosen the best response.0is there anything simple enough for 7th grade math

j814wong
 2 years ago
Best ResponseYou've already chosen the best response.2I'm afraid that's the most basic one. It's just the difference in start and ending velocities divided by the time between the times at which the start and ending velocities are. For example, let's say that the initial velocity is 0 m/s at 0 seconds and the final velocity is 5 m/s 1 second latter. The acceleration would be calculated as (5 m/s  0m/s)/(1 s  0 s)

sami2012
 2 years ago
Best ResponseYou've already chosen the best response.0let me search it up on google

j814wong
 2 years ago
Best ResponseYou've already chosen the best response.2For 7th grade math, that's probably the only other formula you'll ever have to use for acceleration unless another one is given for more advance questions.

j814wong
 2 years ago
Best ResponseYou've already chosen the best response.2Sure. Oh and one other thing, the triangle simple is the delta symbol which means "change in" or "difference" between values.

sami2012
 2 years ago
Best ResponseYou've already chosen the best response.0http://lmgtfy.com/?q=what+is+the+formula+to+calculate+ACCELERATION

sami2012
 2 years ago
Best ResponseYou've already chosen the best response.0@j814wong so what would be the answer to : what is the acceleration of an object that starts stopped and after 5 seconds is going 25m/s

j814wong
 2 years ago
Best ResponseYou've already chosen the best response.2a = Δv/Δt = (vfinal  vinitial) / (tfinal  tinitial) = (25 m/s  0 m/s)/(5 s  0s) Starting stop means a 0 m/s at the initial time or 0s. You are also given the final times for the calculation of 25 m/s after 5 seconds. Just plug in.
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