## chloecv1 3 years ago 1/10k-1/15=-1/6

1. chloecv1

|dw:1350007681277:dw|

2. viniterranova

|dw:1350009040313:dw|

3. .Sam.

|dw:1350019006255:dw|

4. Hero

I hate questions like this because you don't know if the k is in the numerator or the denominator.

5. Kelamun

If the k is out in front of the fraction then it is in the numerator.

6. Hero

Not exactly true. It could also be $\frac{1}{10k}-\frac{1}{15}=-\frac{1}{6}$ The only way to truly avoid the confusion is to use parentheses: (1/10)*k-1/15=-1/6

7. Hero

There's little reason to argue about this. The ambiguity is clearly present and I have run into similar situations in the past. Sometimes the variable is in the denominator, sometimes in the numerator. The only way to avoid the ambiguity is to use proper parentheses when posting a fraction linearly.

8. Kelamun

$\frac{1}{10}k-\frac{1}{15}=-\frac{1}{6}$ is equivalent to $\frac{1}{10}*\frac{k}{1}-\frac{1}{15}=-\frac{1}{6}$

9. Hero

If @chloecv1 had posted the fractions vertically, then it would be more obvious. But she posted it LINEARLY. Do you get what I am saying are will you continue to deny the ambiguity?

10. Hero

You seem to be denying the possibility that if someone posts 1/10k-1/15=-1/6, then there's no way the k would be in the denominator.

11. Kelamun

Her linearly written picture looked much more like the k was on the outside, and therefore in the numerator. I do understand the ambiguity of her horizontal post.

12. Kelamun

*vertically written picture.

13. Hero

"looks more like" isn't the same as actuality. "looks like" in your case is the equivalent of making an assumption.

14. Kelamun

In either case, the problem works out in essentially the same manner. I did assume, yes.