The equation x^2y+2xy^3=8 defines y as a function of x, y=f(x), near x=2, y =1.
Find the slope of the curve x^2y+2xy^3=8 when x=2, y=1
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Do you know how to find the derivative?
Yeah, do we just find the derivative and plug in the points?
Yes find the derivative of both sides with respect to x
And then replace x with 2 and y with 1
Not the answer you are looking for? Search for more explanations.
What does this part of the question mean? y=f(x), near x=2, y =1.
it means that the curve itself might not represent a function, because it does not pass the "vertical line test" but "locally" it is a function, that is, near the point it does represent a function
in practical value, you can ignore that statement and proceed as myininaya said
Ahh, thank you satellite, makes more sense now.
But this point isn't even on the curve.....
@myininaya \[2xy+x^2y'+2y^3+2x3y^2y' = 0\]
I got this when I differentiated both sides, but how do I get y'?