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whats the limit of the following function? could somebody help me pleasE?
 one year ago
 one year ago
whats the limit of the following function? could somebody help me pleasE?
 one year ago
 one year ago

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appleduardoBest ResponseYou've already chosen the best response.0
\[\frac{ \sqrt{2t}\sqrt{2} }{ t }\]
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
first you want to multiply the top and bottom by the reciprocal of the top
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
\[\sqrt{2t}+\sqrt{2}\]
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
multiply top and bottom by that, and what do you get?
 one year ago

appleduardoBest ResponseYou've already chosen the best response.0
yeep, but then i'll get this: \[\frac{ 2t2 }{ t(\sqrt{2t})+\sqrt{2}}\]
 one year ago

appleduardoBest ResponseYou've already chosen the best response.0
ill get:\[\frac{ t }{ t(\sqrt{2t} +\sqrt{2}) }\]
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
also, the denominator should be \[t(\sqrt{2t}+\sqrt{2})\]
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
correct. now can you do anything with the top and bottom t's?
 one year ago

appleduardoBest ResponseYou've already chosen the best response.0
is it right to cancel a negative t with a positive t ?
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
well, you just cancel the t's, the negative would stay.
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
so you would get \[\frac{ 1 }{ \sqrt{2t}+\sqrt{2} }\]
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
now you can take the limit directly by plugging in 0.
 one year ago

appleduardoBest ResponseYou've already chosen the best response.0
:O so the limit is: 0.353509207 ?
 one year ago

nasrynBest ResponseYou've already chosen the best response.1
well, I suppose if you want to do it that way, I would just say \[\frac{ 1 }{ 2\sqrt{2} }\]
 one year ago

appleduardoBest ResponseYou've already chosen the best response.0
oh God youre a genius! thank you so much!!!
 one year ago
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