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appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sqrt{2t}\sqrt{2} }{ t }\]

nasryn
 2 years ago
Best ResponseYou've already chosen the best response.1first you want to multiply the top and bottom by the reciprocal of the top

nasryn
 2 years ago
Best ResponseYou've already chosen the best response.1multiply top and bottom by that, and what do you get?

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0yeep, but then i'll get this: \[\frac{ 2t2 }{ t(\sqrt{2t})+\sqrt{2}}\]

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0ill get:\[\frac{ t }{ t(\sqrt{2t} +\sqrt{2}) }\]

nasryn
 2 years ago
Best ResponseYou've already chosen the best response.1also, the denominator should be \[t(\sqrt{2t}+\sqrt{2})\]

nasryn
 2 years ago
Best ResponseYou've already chosen the best response.1correct. now can you do anything with the top and bottom t's?

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0is it right to cancel a negative t with a positive t ?

nasryn
 2 years ago
Best ResponseYou've already chosen the best response.1well, you just cancel the t's, the negative would stay.

nasryn
 2 years ago
Best ResponseYou've already chosen the best response.1so you would get \[\frac{ 1 }{ \sqrt{2t}+\sqrt{2} }\]

nasryn
 2 years ago
Best ResponseYou've already chosen the best response.1now you can take the limit directly by plugging in 0.

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0:O so the limit is: 0.353509207 ?

nasryn
 2 years ago
Best ResponseYou've already chosen the best response.1well, I suppose if you want to do it that way, I would just say \[\frac{ 1 }{ 2\sqrt{2} }\]

appleduardo
 2 years ago
Best ResponseYou've already chosen the best response.0oh God youre a genius! thank you so much!!!
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