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\[\frac{ x ^{3} -1 }{ \sqrt{x}-3 }\]

x-->1

Is x-3 under the square root or just x?

nope, is (√x) - 3

Then simply plug 1 in for x.

m but ill get 0 in the numerator, and -2 in the denominator, so how can i find the limit?

That is the limit. What is 0 divided by anything?

0 divided by anything is 0. The limit is 0.

thank you so much!! :P very helpful