Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
AJW99
Group Title
Let f(x)=(x^2)tan^1(8x) find f'(x)
I know that the derivative of arctan is 1/(1+x^2)
So, when I applied the product rule I got (x^2)(1/(1+8x^2))+(arctan(8x))(2x). But this isn't correct. Where am I going wrong on this problem?
 one year ago
 one year ago
AJW99 Group Title
Let f(x)=(x^2)tan^1(8x) find f'(x) I know that the derivative of arctan is 1/(1+x^2) So, when I applied the product rule I got (x^2)(1/(1+8x^2))+(arctan(8x))(2x). But this isn't correct. Where am I going wrong on this problem?
 one year ago
 one year ago

This Question is Closed

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
\[(8x)^2 \neq 8x^2\]
 one year ago

AJW99 Group TitleBest ResponseYou've already chosen the best response.0
If I switch it to be 8x^2 it still isn't correct
 one year ago

AJW99 Group TitleBest ResponseYou've already chosen the best response.0
(8x)^2 doesn't work either
 one year ago

Jemurray3 Group TitleBest ResponseYou've already chosen the best response.0
If \[f(x) = x^2\tan^{1}(8x) \] then \[f'(x) = 2x\tan^{1}(8x) + \frac{8x^2}{1+64x^2}\] You have to use the chain rule or the last part.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.