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helpmeplz311

  • 2 years ago

How to Work out the nth term in the sequences below? http://s1274.beta.photobucket.com/user/hmp311/media/7778AD32-3261-48EB-BA9D-119F07AA70C8-1004-00000419CAFB720A_zpsaf8eeb58.jpg.html?sort=3&o=0 Note: I keep asking this and I get a formula: nth term = dn + (a - d)

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  1. helpmeplz311
    • 2 years ago
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    @lgbasallote @nincompoop

  2. helpmeplz311
    • 2 years ago
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    Please help:(

  3. lgbasallote
    • 2 years ago
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    what exactly are you asking?

  4. lgbasallote
    • 2 years ago
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    sequence of what?

  5. helpmeplz311
    • 2 years ago
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    I dont undersyand how to create a formula.

  6. helpmeplz311
    • 2 years ago
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    The worksheet is at the link above.

  7. lgbasallote
    • 2 years ago
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    i see many sequences

  8. helpmeplz311
    • 2 years ago
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    It says you have to work out the terms asked for, create a formula.

  9. helpmeplz311
    • 2 years ago
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    Actually,all of them. I uave to turn this in today.

  10. lgbasallote
    • 2 years ago
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    well...the formula for arithmetic sequence is what you say \[\huge a_n = a_1 + (n-1)d\] where: an is the last term a1 is the first term n is the number of terms d is the common difference

  11. helpmeplz311
    • 2 years ago
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    Please know I am in eight grade.

  12. lgbasallote
    • 2 years ago
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    for example 1, 9, 17, 25, 33,... find the 50th term an would be a50 because a50 is the last term a1 will be 1 because it's the first term n would be 50 because you're looking for the 50th term so you have 50 terms d would be 8 because it adds 8 each number (1 + 8 = 9; 9 + 8 = 17; etc) so if you substitute.. \[\huge a_{50} = 1 + (50 - 1)8\] \[\huge a_{50} = 1 + 49 (8)\] \[\huge a_{50 } = 1 + 392\] \[\huge a_{50} = 393\] so the 50th term is 393 in my example

  13. lgbasallote
    • 2 years ago
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    if you're old enough to learn sequences then you're old enough to learn this

  14. helpmeplz311
    • 2 years ago
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    Ok..'reading'

  15. helpmeplz311
    • 2 years ago
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    may i try o e?

  16. lgbasallote
    • 2 years ago
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    sure

  17. helpmeplz311
    • 2 years ago
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    From my homework.

  18. helpmeplz311
    • 2 years ago
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    ill write in othere first amd then type it on here.

  19. lgbasallote
    • 2 years ago
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    sure

  20. helpmeplz311
    • 2 years ago
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    a44=8+(5-1)9

  21. helpmeplz311
    • 2 years ago
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    number 7

  22. helpmeplz311
    • 2 years ago
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    is that correct?

  23. lgbasallote
    • 2 years ago
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    let me check...

  24. helpmeplz311
    • 2 years ago
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    ok

  25. lgbasallote
    • 2 years ago
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    number 7 is looking for the 50th term not the 44th

  26. helpmeplz311
    • 2 years ago
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    You said a1 was the last term,which in this case is 44

  27. lgbasallote
    • 2 years ago
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    i think you're confused... 8, 17, 26, 35, 44, .... this doesn't mean 44 is the last term "..." means the sequence continues 8, 17, 26, 35, 44, 53, 62, 71 and so on

  28. lgbasallote
    • 2 years ago
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    that means the last term is the 50th term because that's what you're looking for make sense?

  29. helpmeplz311
    • 2 years ago
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    ohhhh

  30. helpmeplz311
    • 2 years ago
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    well, if we erased the 44, would it be correct?

  31. lgbasallote
    • 2 years ago
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    nope. you used 5 as your n

  32. helpmeplz311
    • 2 years ago
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    im sorry.

  33. lgbasallote
    • 2 years ago
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    like i said, the sequence doesn't stop at 44 so there are more than 5 terms

  34. lgbasallote
    • 2 years ago
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    since you're looking for the 50th term, there would be 50 terms make sense?

  35. helpmeplz311
    • 2 years ago
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    yes

  36. lgbasallote
    • 2 years ago
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    good. so rewrite your solution

  37. helpmeplz311
    • 2 years ago
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    wait it shouldve been 50 right

  38. helpmeplz311
    • 2 years ago
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    a50=8+(50-1)9

  39. lgbasallote
    • 2 years ago
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    right. now solve it

  40. helpmeplz311
    • 2 years ago
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    thatll give me the 50th term?

  41. helpmeplz311
    • 2 years ago
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    do you solve for a in the a50?

  42. lgbasallote
    • 2 years ago
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    no... a50 means \(a _{50}\) that means 50th term

  43. lgbasallote
    • 2 years ago
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    just solve the right side

  44. helpmeplz311
    • 2 years ago
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    -2?

  45. helpmeplz311
    • 2 years ago
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    n

  46. helpmeplz311
    • 2 years ago
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    no

  47. lgbasallote
    • 2 years ago
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    how'd you get -2?

  48. helpmeplz311
    • 2 years ago
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    umm,let me tru again

  49. helpmeplz311
    • 2 years ago
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    web2.0calc

  50. helpmeplz311
    • 2 years ago
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    ooo the a50 doesnt matter when solving

  51. lgbasallote
    • 2 years ago
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    yes

  52. helpmeplz311
    • 2 years ago
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    513?

  53. helpmeplz311
    • 2 years ago
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    i lost connection

  54. helpmeplz311
    • 2 years ago
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    back,

  55. helpmeplz311
    • 2 years ago
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    was i right?

  56. lgbasallote
    • 2 years ago
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    you solved 8 + (50-1)9 right?

  57. helpmeplz311
    • 2 years ago
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    yes

  58. lgbasallote
    • 2 years ago
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    did you use a calculator?

  59. helpmeplz311
    • 2 years ago
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    yes i was supposed to use order of operations?

  60. lgbasallote
    • 2 years ago
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    i see what you did (8 + 50 - 1)* 9

  61. lgbasallote
    • 2 years ago
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    that is wrong

  62. helpmeplz311
    • 2 years ago
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    *sigh* ok

  63. lgbasallote
    • 2 years ago
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    you have to do (50 -1) then multiply it to 9 then add 8

  64. helpmeplz311
    • 2 years ago
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    order of ops.

  65. lgbasallote
    • 2 years ago
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    PEMDAS PARENTHESIS expoent MULTIPLICATION division ADDITION subtraction did you forget this?

  66. helpmeplz311
    • 2 years ago
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    no, thats what order of operations is

  67. lgbasallote
    • 2 years ago
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    parenthesis is (50 - 1) multiplication is (50-1)*9 addition is 8 + (50-1)*9

  68. lgbasallote
    • 2 years ago
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    that means you do 50 - 1 first

  69. helpmeplz311
    • 2 years ago
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    o. so, i use that formula, substitute,and solve right side?

  70. lgbasallote
    • 2 years ago
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    yes

  71. helpmeplz311
    • 2 years ago
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    THANK YOU

  72. lgbasallote
    • 2 years ago
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    welcome

  73. helpmeplz311
    • 2 years ago
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    hi amistre

  74. lgbasallote
    • 2 years ago
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    i hope im not in trouble @amistre64

  75. amistre64
    • 2 years ago
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    finally got to the end of it :) howdy!

  76. helpmeplz311
    • 2 years ago
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    howdy,sir

  77. helpmeplz311
    • 2 years ago
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    you mean the end of my endless question?

  78. amistre64
    • 2 years ago
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    i havent seen the links yet, but lgbas stuff looks good so far yeah, these things can get rather lengthy, but thats the way we like to see them. lots of interaction and studying instead of rote answers

  79. helpmeplz311
    • 2 years ago
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    am i in trouble

  80. amistre64
    • 2 years ago
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    lol, not that i can see :) as long as your trying to learn that material you are fine

  81. helpmeplz311
    • 2 years ago
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    yes imam.

  82. amistre64
    • 2 years ago
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    they all look to be arithmetic progressions, so you can apply the same techniques to all of them

  83. lgbasallote
    • 2 years ago
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    i'd like to know though @amistre64 do you know what dn + (a-d) means?

  84. lgbasallote
    • 2 years ago
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    it looks like the formula for arithmetic progression....but it looks weird

  85. amistre64
    • 2 years ago
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    its another way to express the sequence but for n starting at 0 i believe

  86. helpmeplz311
    • 2 years ago
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    amistre can i fan u

  87. lgbasallote
    • 2 years ago
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    dn looks really weird

  88. amistre64
    • 2 years ago
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    dn + (a-d) dn - d + a d(n-1) + a

  89. amistre64
    • 2 years ago
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    you can fan whomever you wish

  90. lgbasallote
    • 2 years ago
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    ...clever

  91. amistre64
    • 2 years ago
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    i think if i get anymore fans the site will collapse into an infinitly large black hole tho so be careful if you do :)

  92. amistre64
    • 2 years ago
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    have you gone over how to find the terms used: a, d, n ?

  93. helpmeplz311
    • 2 years ago
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    yes

  94. amistre64
    • 2 years ago
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    good, cause one you know how to get those, the rest is just simple arithmetic

  95. amistre64
    • 2 years ago
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    *cause once you know

  96. helpmeplz311
    • 2 years ago
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    d common difference

  97. amistre64
    • 2 years ago
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    how do you find the common difference of the sequence?

  98. helpmeplz311
    • 2 years ago
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    subtract.

  99. amistre64
    • 2 years ago
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    right, subtract the first term from the second term problem 10: 7 ,13, 19, ... d = 13-7 = 6 right?

  100. helpmeplz311
    • 2 years ago
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    yes sirr

  101. amistre64
    • 2 years ago
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    and what does the "a" in the formula refer to?

  102. helpmeplz311
    • 2 years ago
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    a refers to a term

  103. amistre64
    • 2 years ago
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    yes, but there is "a" special a that we need to use in the formula itself. the FIRST term. In the problem im working thru, that would be: 7 d=6, a=7 and what does "n" mean?

  104. amistre64
    • 2 years ago
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    im going to use a different but equal notation for the formula: \[f(n)=a+d(n-1)\] \[f(n)=7+6(n-1)\]

  105. amistre64
    • 2 years ago
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    you can replace \(f(n)\) with \(a_n\) if you want, its just a placeholder

  106. amistre64
    • 2 years ago
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    the "n" is reserved for the position of the term we want to find. in this case, the 90th term \[f(n)=7+6(n-1)\] \[f(90)=7+6(90-1)\] \[f(90)=7+6(89)\] \[f(90)=7+534\] \[f(90)=541\]

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