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lgbasallote
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show that at least 3 of any 25 days chosen must fall in the same month of the year
 2 years ago
 2 years ago
lgbasallote Group Title
show that at least 3 of any 25 days chosen must fall in the same month of the year
 2 years ago
 2 years ago

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CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
Including leap years?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
Simple pigeonhole principle.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
Only 12 months, 25 days
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
What if the 25 days span two years?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
He means 25 days of the same year. Otherwise this would not be true.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
Suppose you try to distribute them as evenly as you can with the minimal amount of days per month, that would be: 24/12 = 2 days per month, but you have 1 more day left over.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
So whatever month you add it to, that month will end up with exactly 3 days.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
if you decide to give a certain month only 1 day, then you'll have to have 4 days in a different month.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
It's basically saying that if I have two boxes and 3 balls, and I have to put those balls into the boxes, one box is going to have more than 2 balls
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
I meant more than 1 ball
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
it's proving...not a question
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
anyway...
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
what were you saying @bahrom7893 ?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
Well i just proved it. Consider the worst case scenario, where you would want to distribute the days into the months, so that each month has the minimum amount of days. Put one day into each month, that would give you 12 months, with one day in each, and you have 13 days remaining to be distributed. Repeat  add a day to each month, that would leave you with 12 months, with two days in each, and you still have 1 day left to be distributed.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
Since the number of days in each month is already 2, whichever month you decide to put the last day in, is going to have 3 days in it.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
And that is the proof.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
hmm that does make sense...
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
if you decide to give 0 days to one month, you're already screwed because you have more days left. So in these types of problems you'd want to distribute a minimum amount of whatever you're distributing, evenly among the boxes.
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
and then see if you have any leftovers.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
well ot's at;east...so i suppose even if you assign 0 days to one month...it will still make one month have 3 days
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
it will have one month have 4 days and one month to haave 3 days i believe
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
it still fits the condition right?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
yea, if you decrease the number of months or increase the number of days, it will fit the condition. If you decrease the number of days, or increase the number of months (which is silly) then it won't.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
so no matter what happens...you're right?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.2
yea, for example, put 0 days in one month. That would be pretty much the same as getting rid of that month. So now you have to distribute 25 days into 11 months. Do what I said. Step 1: 11 months, one day in each, 14 days remaining Step 2: 11 months, two days in each, 3 days remaining So now you have 3 additional months, and whichever month you add them to, is going to have at least 3 days.
 2 years ago
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