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shubhamsrg
 3 years ago
geometry + similarity question i'd guess..
PQRS is a //gm
PS//ZX
PZ / QZ = 2/3
find XY/SQ =?
shubhamsrg
 3 years ago
geometry + similarity question i'd guess.. PQRS is a //gm PS//ZX PZ / QZ = 2/3 find XY/SQ =?

This Question is Closed

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0Is there a second parallelogram adjacent to the fist? I'm trying to imagine the scenario.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350050559015:dw

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0I can start by stating the obvious: SX/QX = 2/3.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0hmm,,yep.. here's what i tried to do.. dw:1350051162014:dw

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0will this be helpful ?

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0YM // to XZ? Hmm, yes, possibly..

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0further,, we may also see.. dw:1350051445715:dw let PZ = 2l thenZQ = 3l let ZM = j then MQ = 3l j

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350051539893:dw we can easily see a/(a+b+c) = 2/5 b/(a+b+c)= j/5l c/(a+b+c) =(3l j)/5l we need to find numerical value of b/(a+b+c) where, we know that a/(b+c) = 2/3 any help ?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0nopes according to my book i mean,,i dont know! :P what was your solution ?

estudier
 3 years ago
Best ResponseYou've already chosen the best response.2It's a/5a whatever that is...:)

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0nopes..not that either..

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0Here's what I got so far. I let PZ=2 and ZQ=3 since that satisfies the ratio. XQ/ZQ = SX/PZ > XQ/3 = SX/2 XQ/ZQ = 2/3 > XQ = 2 SX/PZ = XQ/ZQ > SX/2 = 2/3 SX = 4/3 SX+XQ = 10/3

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0XQ/ZQ = SX/PZ ?? how sir ?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0ohh.lol..sorry,,i didnt compare with figure properly that one..hmm..

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0XQ/ZQ = 2/3 > XQ = 2 will that be right to conclude ?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0am saying this since this would be another assumption based on an earlier assumtion that PZ=2 and ZQ = 3

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0I think so, that's what I got. I'm still playing around with the proportions to find XY or YQ..

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0That wasn't an assumption, that was an arbitrary choice. There's no restriction on what PZ and ZQ are as long as they satisfy the ratio.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0but, in generailty, we have PZ = 2m and ZQ = 3m you assumed m=1 ,,fair enough now XQ/ZQ = 2/3 XQ = 2n => ZQ = 3n this came from the fact m =1// now will that be right in saying n=1 also when m=1 already ?

estudier
 3 years ago
Best ResponseYou've already chosen the best response.2SY/YQ should be 5/2 I think

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0If you're using 2m and 3m and 2n and 3n, just because you can choose m=1 at first, that doesn't make n=1.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0thats what am saying,,but you took both m and n = 1 ..

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0neither of those @sauravshakya and @estudier ans is 9/40

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0I never bothered with m or n at all. I set PZ=2 and ZQ=3 and the rest followed.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0PZ=2 and ZQ = 3 made you reach till XQ/ZQ = 2/3 but XQ = 2 and ZQ=3 i guess wont be right..

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0@ganeshie8 am quite eager to know..

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1\(\triangle YZX \sim \triangle YRQ\)

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0oh,,i never really saw that,,cool !

estudier
 3 years ago
Best ResponseYou've already chosen the best response.2I wasn't saying 5/3 was the answer, I was saying that if RZ divides PQ in ratio 2 to 3 then Y divides SQ in ratio 2+3 to 3 (imagine RZ sliding along QP until it becomes a diagonal of the //gram)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1and, \(\frac{ZQ}{PQ} = \frac{3}{5}\)

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1those two are sufficient to get to 9/40

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0am sorry but am still unable to @ganeshie8 :

CliffSedge
 3 years ago
Best ResponseYou've already chosen the best response.0I was able to get it using estudier's SY/YQ=5/3. SY + YQ = SQ = 10/3 SY = 10/3  YQ (10/3/YQ)/YQ = 5/3 > YQ=5/4 SY = 25/12 XY = SYSX > XY = 3/4 XY/SQ = (3/4)/(10/3) = 9/40. QED.

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0ohh,,wait,,leme try again @ganeshie8

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.1ok else id post... :) im seeing estudier posts.. .

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0thats really amazing.. gotcha @ganeshie8 @estudier @CliffSedge thanks all..really really great !!
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