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geometry + similarity question i'd guess..
PQRS is a //gm
PS//ZX
PZ / QZ = 2/3
find XY/SQ =?
 one year ago
 one year ago
geometry + similarity question i'd guess.. PQRS is a //gm PS//ZX PZ / QZ = 2/3 find XY/SQ =?
 one year ago
 one year ago

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CliffSedgeBest ResponseYou've already chosen the best response.0
Is there a second parallelogram adjacent to the fist? I'm trying to imagine the scenario.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
dw:1350050559015:dw
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
I can start by stating the obvious: SX/QX = 2/3.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
hmm,,yep.. here's what i tried to do.. dw:1350051162014:dw
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
will this be helpful ?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
YM // to XZ? Hmm, yes, possibly..
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
further,, we may also see.. dw:1350051445715:dw let PZ = 2l thenZQ = 3l let ZM = j then MQ = 3l j
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
dw:1350051539893:dw we can easily see a/(a+b+c) = 2/5 b/(a+b+c)= j/5l c/(a+b+c) =(3l j)/5l we need to find numerical value of b/(a+b+c) where, we know that a/(b+c) = 2/3 any help ?
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
nopes according to my book i mean,,i dont know! :P what was your solution ?
 one year ago

estudierBest ResponseYou've already chosen the best response.2
It's a/5a whatever that is...:)
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
nopes..not that either..
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Here's what I got so far. I let PZ=2 and ZQ=3 since that satisfies the ratio. XQ/ZQ = SX/PZ > XQ/3 = SX/2 XQ/ZQ = 2/3 > XQ = 2 SX/PZ = XQ/ZQ > SX/2 = 2/3 SX = 4/3 SX+XQ = 10/3
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
XQ/ZQ = SX/PZ ?? how sir ?
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
ohh.lol..sorry,,i didnt compare with figure properly that one..hmm..
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
XQ/ZQ = 2/3 > XQ = 2 will that be right to conclude ?
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
am saying this since this would be another assumption based on an earlier assumtion that PZ=2 and ZQ = 3
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
I think so, that's what I got. I'm still playing around with the proportions to find XY or YQ..
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
That wasn't an assumption, that was an arbitrary choice. There's no restriction on what PZ and ZQ are as long as they satisfy the ratio.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
but, in generailty, we have PZ = 2m and ZQ = 3m you assumed m=1 ,,fair enough now XQ/ZQ = 2/3 XQ = 2n => ZQ = 3n this came from the fact m =1// now will that be right in saying n=1 also when m=1 already ?
 one year ago

estudierBest ResponseYou've already chosen the best response.2
SY/YQ should be 5/2 I think
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
If you're using 2m and 3m and 2n and 3n, just because you can choose m=1 at first, that doesn't make n=1.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
thats what am saying,,but you took both m and n = 1 ..
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
neither of those @sauravshakya and @estudier ans is 9/40
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
I never bothered with m or n at all. I set PZ=2 and ZQ=3 and the rest followed.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
PZ=2 and ZQ = 3 made you reach till XQ/ZQ = 2/3 but XQ = 2 and ZQ=3 i guess wont be right..
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
@ganeshie8 am quite eager to know..
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
\(\triangle YZX \sim \triangle YRQ\)
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
oh,,i never really saw that,,cool !
 one year ago

estudierBest ResponseYou've already chosen the best response.2
I wasn't saying 5/3 was the answer, I was saying that if RZ divides PQ in ratio 2 to 3 then Y divides SQ in ratio 2+3 to 3 (imagine RZ sliding along QP until it becomes a diagonal of the //gram)
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
and, \(\frac{ZQ}{PQ} = \frac{3}{5}\)
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
those two are sufficient to get to 9/40
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
am sorry but am still unable to @ganeshie8 :
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
I was able to get it using estudier's SY/YQ=5/3. SY + YQ = SQ = 10/3 SY = 10/3  YQ (10/3/YQ)/YQ = 5/3 > YQ=5/4 SY = 25/12 XY = SYSX > XY = 3/4 XY/SQ = (3/4)/(10/3) = 9/40. QED.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
ohh,,wait,,leme try again @ganeshie8
 one year ago

ganeshie8Best ResponseYou've already chosen the best response.1
ok else id post... :) im seeing estudier posts.. .
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
thats really amazing.. gotcha @ganeshie8 @estudier @CliffSedge thanks all..really really great !!
 one year ago
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