A community for students.
Here's the question you clicked on:
 0 viewing
amorfide
 4 years ago
So it is time to ask a question of my own, i do not need an entire solution, just what the next step is
amorfide
 4 years ago
So it is time to ask a question of my own, i do not need an entire solution, just what the next step is

This Question is Closed

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0find the values of A and B

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0i did the first step which gives me

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0not sure what to do next

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0@Callisto can you help?

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.0you tagged someone with an "i hate math" picture to a math question?

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0Is it n(2n^2 + 3n 2) on the right side?

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1350056495046:dw Can you simplify it first?

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0which side? left or right

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0Both. There is a common factor.

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0that should be 2n on ther ight

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0Not really.\[\frac{A}{6}n(n+1)(2n+1) +bn= n(n^2 + 3n 2)\]\[n[\frac{A}{6}(n+1)(2n+1)+b] = n(n^2 + 3n 2)\] Cancel the common factor. and expand the left side.

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0you could change b to 6b/6 and take out a factor of 1/6 right?

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0You can, of course. But there is a common factor on both sides that you can cancel, what is it?

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0get rid of n on both sides? if not then i dont know waht the common factor is on both sides

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0Yes! So, now, you get \[\frac{A}{6}(n+1)(2n+1)+b = n^2 + 3n 2\]So, expand the terms on the left. What do you get?

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0now i shall multiply out

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0Not really..\[\frac{A}{6}(2n+1)(n+1) = \frac{A}{6}(2n^2+3n+1) = ...?\]

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0oh and it is 2n² on the right

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0so that means to get 2n² A has to be 6

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0I'm sorry but I have to go now... Basically, you need to expand the first term on the left, combine the like terms and compare the coefficient of x^2, x and constant terms on both sides. Then you can find A and B. As for your expansion, sorry again that it is wrong.

amorfide
 4 years ago
Best ResponseYou've already chosen the best response.0okay thank you! i shall work on this thank you for your help

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0a has to be 6 is correct, I supposed :

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.0Once you find a, then compare the constant term on both sides. You should be able to get b. Good luck :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.