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So it is time to ask a question of my own, i do not need an entire solution, just what the next step is
 one year ago
 one year ago
So it is time to ask a question of my own, i do not need an entire solution, just what the next step is
 one year ago
 one year ago

This Question is Closed

amorfideBest ResponseYou've already chosen the best response.0
dw:1350055553188:dw
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
find the values of A and B
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
i did the first step which gives me
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
dw:1350055629792:dw
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
not sure what to do next
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
@Callisto can you help?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
you tagged someone with an "i hate math" picture to a math question?
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
Is it n(2n^2 + 3n 2) on the right side?
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
dw:1350056495046:dw Can you simplify it first?
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
which side? left or right
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
Both. There is a common factor.
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
dw:1350056560601:dw
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
that should be 2n on ther ight
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
dw:1350056701582:dw
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
Not really.\[\frac{A}{6}n(n+1)(2n+1) +bn= n(n^2 + 3n 2)\]\[n[\frac{A}{6}(n+1)(2n+1)+b] = n(n^2 + 3n 2)\] Cancel the common factor. and expand the left side.
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
you could change b to 6b/6 and take out a factor of 1/6 right?
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
You can, of course. But there is a common factor on both sides that you can cancel, what is it?
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
get rid of n on both sides? if not then i dont know waht the common factor is on both sides
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
Yes! So, now, you get \[\frac{A}{6}(n+1)(2n+1)+b = n^2 + 3n 2\]So, expand the terms on the left. What do you get?
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
now i shall multiply out
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
dw:1350057038246:dw
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
dw:1350057107864:dw
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
Not really..\[\frac{A}{6}(2n+1)(n+1) = \frac{A}{6}(2n^2+3n+1) = ...?\]
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
oh and it is 2n² on the right
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
dw:1350057219369:dw
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
so that means to get 2n² A has to be 6
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
I'm sorry but I have to go now... Basically, you need to expand the first term on the left, combine the like terms and compare the coefficient of x^2, x and constant terms on both sides. Then you can find A and B. As for your expansion, sorry again that it is wrong.
 one year ago

amorfideBest ResponseYou've already chosen the best response.0
okay thank you! i shall work on this thank you for your help
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
a has to be 6 is correct, I supposed :
 one year ago

CallistoBest ResponseYou've already chosen the best response.0
Once you find a, then compare the constant term on both sides. You should be able to get b. Good luck :)
 one year ago
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