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 2 years ago
So it is time to ask a question of my own, i do not need an entire solution, just what the next step is
 2 years ago
So it is time to ask a question of my own, i do not need an entire solution, just what the next step is

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amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0find the values of A and B

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0i did the first step which gives me

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0not sure what to do next

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0@Callisto can you help?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0you tagged someone with an "i hate math" picture to a math question?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Is it n(2n^2 + 3n 2) on the right side?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1350056495046:dw Can you simplify it first?

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0which side? left or right

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Both. There is a common factor.

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0that should be 2n on ther ight

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Not really.\[\frac{A}{6}n(n+1)(2n+1) +bn= n(n^2 + 3n 2)\]\[n[\frac{A}{6}(n+1)(2n+1)+b] = n(n^2 + 3n 2)\] Cancel the common factor. and expand the left side.

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0you could change b to 6b/6 and take out a factor of 1/6 right?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0You can, of course. But there is a common factor on both sides that you can cancel, what is it?

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0get rid of n on both sides? if not then i dont know waht the common factor is on both sides

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Yes! So, now, you get \[\frac{A}{6}(n+1)(2n+1)+b = n^2 + 3n 2\]So, expand the terms on the left. What do you get?

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0now i shall multiply out

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Not really..\[\frac{A}{6}(2n+1)(n+1) = \frac{A}{6}(2n^2+3n+1) = ...?\]

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0oh and it is 2n² on the right

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0so that means to get 2n² A has to be 6

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0I'm sorry but I have to go now... Basically, you need to expand the first term on the left, combine the like terms and compare the coefficient of x^2, x and constant terms on both sides. Then you can find A and B. As for your expansion, sorry again that it is wrong.

amorfide
 2 years ago
Best ResponseYou've already chosen the best response.0okay thank you! i shall work on this thank you for your help

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0a has to be 6 is correct, I supposed :

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.0Once you find a, then compare the constant term on both sides. You should be able to get b. Good luck :)
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