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anonymous
 4 years ago
Find the derivative of f when
f(x) = 2 tan(x) + 3 cot(x)
anonymous
 4 years ago
Find the derivative of f when f(x) = 2 tan(x) + 3 cot(x)

This Question is Closed

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1derivative of tan x is sec^x can't remember derivative of cot x  try googling it first term of derivative is 2 sec^2 x

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1http://www.math.com/tables/derivatives/tableof.htm this link lists derivatives

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sol: let y=f(x) y=2tan(x)+3cot(x) =2dy/dxtanx+3dy/dxcotx =2*sec^2x+3*cosec^2x =2sec^2x3cosec^2x

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1oh ok so f'(x) = 2 sec^2 x  3 csc^2 x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0think they want me to make in ration form its number 3 on the hw i have attached

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats not one of the answer choices

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0muhammand please help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are these questions???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes the document i have attached is the homework i am looking at number 3 specifically

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1ah what they have done is convert the sec and csc to sin and cos

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what is the answer

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.12 sec^2 x  3 csc^2 x = 2 * 1/cos^2 x  3 * 1 / sin^2 x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is not the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have to turn it on in ten minutes

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1well i think it is the answer but its in different form to your choices  i'm trying to figure it out

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1yes  do you agree with that answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer choices r on the document

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0swissgirl please help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer choice are on the paper

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1i know that sandy  but i can't figure out which is equivalent to the sec and csc expression

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm maybe you need to get a common deonmanator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do anyone know the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont need an explainatio just the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nvm the hw is past due now :(

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1there might be a mistake in the paper i'm sure 2sec^2x  3 csc^2 x is correct but u need to convert it

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1hold on  i think I've got it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh I got the answer \( \large {25\cos^2(x) \over \sin^2(x)\cos^2(x)} \)

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1yes  i've converted the to sines and cosines but i can't get any of the choices on the paper yes  i got that  but its not one of the choices

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its the fourth choice

cwrw238
 4 years ago
Best ResponseYou've already chosen the best response.1oh  i've been looking in the wrong place!!!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hahah I know its quite confusing to follow
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