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First step: Take derivative with respect to x on both sides of the equation.

\[\text{What did you get when you did } (2xy)' \text{ and } (y^2)' ?\]

(2xy)' = dy/dx 2y +2x dy/dx and (y^2)' = -2y

Looks incorrect for both

\[(y^n)'=n y ^{n-1} y' \text{ By chain rule } \]