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xmas

  • 3 years ago

ln(x)=-1

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  1. Jonask
    • 3 years ago
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    \[e^{lnx}=e^{-1}\]

  2. Jonask
    • 3 years ago
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    \[x=e^{-1}\]

  3. xmas
    • 3 years ago
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    I thought so. But is x=1/e the same?

  4. xmas
    • 3 years ago
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    Thanks Jonask.

  5. Jonask
    • 3 years ago
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    yes 1/e=e^-1

  6. xmas
    • 3 years ago
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    Good stuff. Thank you again.

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