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NoelGrecoBest ResponseYou've already chosen the best response.0
Can you put some parentheses on the righthand side? It's ambiguous.
 one year ago

MathPhysicsBest ResponseYou've already chosen the best response.0
NoelGreco is right, you gotta clarify that
 one year ago

XaviBest ResponseYou've already chosen the best response.0
If you mean (xsinx+1)/cosx,then use the rule of divide to get ((cosx)(xcosx+sinx)(xsinx+1)(sinx))/(cosx)^2 If you mean xsinx+ 1/cosx,then,find the derivative seperately.Namely,(xcosx+sinx)+secxtanx
 one year ago

pastaBest ResponseYou've already chosen the best response.0
product rule for the first part and quotient for the second
 one year ago

bilgadsBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ \cos ^{2}(x) } + tanx (\frac{ \cos x 1}{ \cos x } )\]
 one year ago

adi171Best ResponseYou've already chosen the best response.0
hmmmm... first use product rule for xsinx... then 1/cosx = secx.... find derivative of secx.. job done
 one year ago
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