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lyssamonet

  • 3 years ago

how do you find the derivative of f(x)=xsinx+1/cosx?

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  1. NoelGreco
    • 3 years ago
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    Can you put some parentheses on the right-hand side? It's ambiguous.

  2. MathPhysics
    • 3 years ago
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    NoelGreco is right, you gotta clarify that

  3. Xavi
    • 3 years ago
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    If you mean (xsinx+1)/cosx,then use the rule of divide to get ((cosx)(xcosx+sinx)-(xsinx+1)(-sinx))/(cosx)^2 If you mean xsinx+ 1/cosx,then,find the derivative seperately.Namely,(xcosx+sinx)+secxtanx

  4. pasta
    • 3 years ago
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    product rule for the first part and quotient for the second

  5. bilgads
    • 3 years ago
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    \[\frac{ x }{ \cos ^{2}(x) } + tanx (\frac{ \cos x -1}{ \cos x } )\]

  6. pasta
    • 3 years ago
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    sinx+cosx-(sinx/cos^2x)

  7. adi171
    • 3 years ago
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    hmmmm... first use product rule for xsinx... then 1/cosx = secx.... find derivative of secx.. job done

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