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NoelGreco Group TitleBest ResponseYou've already chosen the best response.0
Can you put some parentheses on the righthand side? It's ambiguous.
 2 years ago

MathPhysics Group TitleBest ResponseYou've already chosen the best response.0
NoelGreco is right, you gotta clarify that
 2 years ago

Xavi Group TitleBest ResponseYou've already chosen the best response.0
If you mean (xsinx+1)/cosx,then use the rule of divide to get ((cosx)(xcosx+sinx)(xsinx+1)(sinx))/(cosx)^2 If you mean xsinx+ 1/cosx,then,find the derivative seperately.Namely,(xcosx+sinx)+secxtanx
 2 years ago

pasta Group TitleBest ResponseYou've already chosen the best response.0
product rule for the first part and quotient for the second
 2 years ago

bilgads Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x }{ \cos ^{2}(x) } + tanx (\frac{ \cos x 1}{ \cos x } )\]
 2 years ago

pasta Group TitleBest ResponseYou've already chosen the best response.0
sinx+cosx(sinx/cos^2x)
 one year ago

adi171 Group TitleBest ResponseYou've already chosen the best response.0
hmmmm... first use product rule for xsinx... then 1/cosx = secx.... find derivative of secx.. job done
 one year ago
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