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LilVeroDez13

Mid point help!! (attachment) plz help!

  • one year ago
  • one year ago

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  1. LilVeroDez13
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    • one year ago
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  2. TehAustin
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    ini mini miny moe

    • one year ago
  3. LilVeroDez13
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    Haa ;) it dont work that way ;P

    • one year ago
  4. TehAustin
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    Try it it works somtimes

    • one year ago
  5. TehAustin
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    @Zarkon maybe he can answer

    • one year ago
  6. LilVeroDez13
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    Thanks!!

    • one year ago
  7. cwrw238
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    the link asks for the lengths

    • one year ago
  8. LilVeroDez13
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    how do u find that?

    • one year ago
  9. cwrw238
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    midpoint.png

    • one year ago
  10. LilVeroDez13
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    No.. i mean how do u find the lengths

    • one year ago
  11. cwrw238
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    lol - ok segment EF = square root( (5-1)^2 + (-5-(-2)^2) = square root 16+9 = square root 25 = 5

    • one year ago
  12. LilVeroDez13
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    Thanks! Are both lengths gonna b 5?

    • one year ago
  13. cwrw238
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    GH = square root (1^2 + 2^2) = square root 5

    • one year ago
  14. LilVeroDez13
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    Thanks!!! culd u help me with another problem

    • one year ago
  15. cwrw238
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    yes - i think i have time

    • one year ago
  16. LilVeroDez13
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    Ha thanks!

    • one year ago
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  17. cwrw238
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    midpoint = x1 + x2 y1 + y2 ------ ------- , 2 2 here x1 = -2 , x2 = x+2 , y1 = -6 and y2 = x+3

    • one year ago
  18. cwrw238
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    gotta go now...

    • one year ago
  19. chenna
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    if (x1, y1) and (x2, y2) are two points, then the mid point is ( (x1+x2)/2, (y1+y2)/2 )

    • one year ago
  20. LilVeroDez13
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    okk.. but which choice wuld that b? i dont see it

    • one year ago
  21. chenna
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    what did you get?

    • one year ago
  22. LilVeroDez13
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    (x/2, (y-3)/2)?

    • one year ago
  23. chenna
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    yep. Thats the correct answer.

    • one year ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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