anonymous
  • anonymous
Mid point help!! (attachment) plz help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
ini mini miny moe
anonymous
  • anonymous
Haa ;) it dont work that way ;P

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anonymous
  • anonymous
Try it it works somtimes
anonymous
  • anonymous
@Zarkon maybe he can answer
anonymous
  • anonymous
Thanks!!
cwrw238
  • cwrw238
the link asks for the lengths
anonymous
  • anonymous
how do u find that?
cwrw238
  • cwrw238
midpoint.png
anonymous
  • anonymous
No.. i mean how do u find the lengths
cwrw238
  • cwrw238
lol - ok segment EF = square root( (5-1)^2 + (-5-(-2)^2) = square root 16+9 = square root 25 = 5
anonymous
  • anonymous
Thanks! Are both lengths gonna b 5?
cwrw238
  • cwrw238
GH = square root (1^2 + 2^2) = square root 5
anonymous
  • anonymous
Thanks!!! culd u help me with another problem
cwrw238
  • cwrw238
yes - i think i have time
anonymous
  • anonymous
Ha thanks!
1 Attachment
cwrw238
  • cwrw238
midpoint = x1 + x2 y1 + y2 ------ ------- , 2 2 here x1 = -2 , x2 = x+2 , y1 = -6 and y2 = x+3
cwrw238
  • cwrw238
gotta go now...
anonymous
  • anonymous
if (x1, y1) and (x2, y2) are two points, then the mid point is ( (x1+x2)/2, (y1+y2)/2 )
anonymous
  • anonymous
okk.. but which choice wuld that b? i dont see it
anonymous
  • anonymous
what did you get?
anonymous
  • anonymous
(x/2, (y-3)/2)?
anonymous
  • anonymous
yep. Thats the correct answer.

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