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LilVeroDez13

  • 3 years ago

Mid point help!! (attachment) plz help!

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  1. LilVeroDez13
    • 3 years ago
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  2. TehAustin
    • 3 years ago
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    ini mini miny moe

  3. LilVeroDez13
    • 3 years ago
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    Haa ;) it dont work that way ;P

  4. TehAustin
    • 3 years ago
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    Try it it works somtimes

  5. TehAustin
    • 3 years ago
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    @Zarkon maybe he can answer

  6. LilVeroDez13
    • 3 years ago
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    Thanks!!

  7. cwrw238
    • 3 years ago
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    the link asks for the lengths

  8. LilVeroDez13
    • 3 years ago
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    how do u find that?

  9. cwrw238
    • 3 years ago
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    midpoint.png

  10. LilVeroDez13
    • 3 years ago
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    No.. i mean how do u find the lengths

  11. cwrw238
    • 3 years ago
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    lol - ok segment EF = square root( (5-1)^2 + (-5-(-2)^2) = square root 16+9 = square root 25 = 5

  12. LilVeroDez13
    • 3 years ago
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    Thanks! Are both lengths gonna b 5?

  13. cwrw238
    • 3 years ago
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    GH = square root (1^2 + 2^2) = square root 5

  14. LilVeroDez13
    • 3 years ago
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    Thanks!!! culd u help me with another problem

  15. cwrw238
    • 3 years ago
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    yes - i think i have time

  16. LilVeroDez13
    • 3 years ago
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    Ha thanks!

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  17. cwrw238
    • 3 years ago
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    midpoint = x1 + x2 y1 + y2 ------ ------- , 2 2 here x1 = -2 , x2 = x+2 , y1 = -6 and y2 = x+3

  18. cwrw238
    • 3 years ago
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    gotta go now...

  19. chenna
    • 3 years ago
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    if (x1, y1) and (x2, y2) are two points, then the mid point is ( (x1+x2)/2, (y1+y2)/2 )

  20. LilVeroDez13
    • 3 years ago
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    okk.. but which choice wuld that b? i dont see it

  21. chenna
    • 3 years ago
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    what did you get?

  22. LilVeroDez13
    • 3 years ago
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    (x/2, (y-3)/2)?

  23. chenna
    • 3 years ago
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    yep. Thats the correct answer.

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