LilVeroDez13
Mid point help!! (attachment) plz help!



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LilVeroDez13
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TehAustin
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ini mini miny moe

LilVeroDez13
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Haa ;) it dont work that way ;P

TehAustin
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Try it it works somtimes

TehAustin
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@Zarkon maybe he can answer

LilVeroDez13
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Thanks!!

cwrw238
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the link asks for the lengths

LilVeroDez13
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how do u find that?

cwrw238
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midpoint.png

LilVeroDez13
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No.. i mean how do u find the lengths

cwrw238
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lol  ok
segment EF = square root( (51)^2 + (5(2)^2)
= square root 16+9
= square root 25
= 5

LilVeroDez13
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Thanks! Are both lengths gonna b 5?

cwrw238
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GH
= square root (1^2 + 2^2) = square root 5

LilVeroDez13
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Thanks!!! culd u help me with another problem

cwrw238
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yes  i think i have time

LilVeroDez13
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Ha thanks!

cwrw238
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midpoint = x1 + x2 y1 + y2
  ,
2 2
here x1 = 2 , x2 = x+2 , y1 = 6 and y2 = x+3

cwrw238
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gotta go now...

chenna
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if (x1, y1) and (x2, y2) are two points, then the mid point is
( (x1+x2)/2, (y1+y2)/2 )

LilVeroDez13
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okk.. but which choice wuld that b? i dont see it

chenna
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what did you get?

LilVeroDez13
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(x/2, (y3)/2)?

chenna
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yep. Thats the correct answer.