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Mid point help!! (attachment) plz help!

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1 Attachment
ini mini miny moe
Haa ;) it dont work that way ;P

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Other answers:

Try it it works somtimes
@Zarkon maybe he can answer
the link asks for the lengths
how do u find that?
No.. i mean how do u find the lengths
lol - ok segment EF = square root( (5-1)^2 + (-5-(-2)^2) = square root 16+9 = square root 25 = 5
Thanks! Are both lengths gonna b 5?
GH = square root (1^2 + 2^2) = square root 5
Thanks!!! culd u help me with another problem
yes - i think i have time
Ha thanks!
1 Attachment
midpoint = x1 + x2 y1 + y2 ------ ------- , 2 2 here x1 = -2 , x2 = x+2 , y1 = -6 and y2 = x+3
gotta go now...
if (x1, y1) and (x2, y2) are two points, then the mid point is ( (x1+x2)/2, (y1+y2)/2 )
okk.. but which choice wuld that b? i dont see it
what did you get?
(x/2, (y-3)/2)?
yep. Thats the correct answer.

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