Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350067985984:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I have the solution, looking for help to understand the process
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
lol .. "Improper Integral" is not quite the term you describe it.
 2 years ago

ipm1988 Group TitleBest ResponseYou've already chosen the best response.0
break x^4 in (x^2)^2 then use substitution
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350068067914:dw
 2 years ago

ipm1988 Group TitleBest ResponseYou've already chosen the best response.0
are you familiar with last three special integrals formula
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
three special integral formula? not sure which one you are referring to
 2 years ago

ipm1988 Group TitleBest ResponseYou've already chosen the best response.0
did you use double substitution
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
let x^2 = u sub ... this would end up into inverse typerbolic function.
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350068248916:dwthese two?
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
well ... you can try that. but I'll give you a shortcut.
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
ok I will love to see the shortcut
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
look at the the inverse hyperbolic of sine http://en.wikipedia.org/wiki/Inverse_hyperbolic_function
 2 years ago

ipm1988 Group TitleBest ResponseYou've already chosen the best response.0
@experimentX me to please
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
dw:1350068353134:dw
 2 years ago

ipm1988 Group TitleBest ResponseYou've already chosen the best response.0
@experimentX nice one
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I see it is the first one
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
dw:1350068400466:dw probably you would get inverse hyperbolic for this types ... but generally formula is given as dw:1350068503882:dw ... lol all these forms are inverse hyperbolic function. people usually don't use these.
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350068751083:dw solution manual has this as a second step
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
hmm ... it really was improper intgral!!
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
Is this because of the square root function's domain being continuous on [a, infinity)?
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
dw:1350068740846:dw Start with a right triangle Label the sides such that the inside of that radical you have above appears somewhere. dw:1350068780160:dw So we will use substitution \[x^2=\tan( \theta) \] dw:1350068798338:dw Now we need to take derivative of both sides of our substitution \[2x dx=\sec^2( \theta) d \theta \]
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
this doesn't converge.
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
ok I am following you so far
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
yes in the end, I know this diverges. I know the final answer, just trying to learn the process or understand the process (is a better description)
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
\[2x dx=\sec^2(\theta) d \theta = > x dx =\frac{1}{2} \sec^2(\theta) d \theta \] Now you go to your little expression and make your "suby's" happen.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
dw:1350068915623:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350069081160:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I guess I am not sure in the set up why [a, infinity) was used vs (infinity, b] or (infinity, infinity) is it because of the domain of the square root function
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
@precal I'm not sure what you are asking
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
In the definition of Improper integrals over infinite intervals I have 3 definitions
 2 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
It is improper integral because of that infinity thing.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
probably with definition of improper integral ... when you have limit goes to infinity ... you have improper integral of first kind.
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350069479305:dw provided the limit exists
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I should mention that if f is continuous on [a,infinity), then for the above first definition
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
2nd definition If f is continuous on (infinty, b], thendw:1350069615971:dw provided the limit exists.
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
dw:1350069732672:dw this is called improper integral of First Kind.
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
3rd definition If f is continuous on (infinity, infinity), then dw:1350069715530:dw probided both limits exist, where c is any real number
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
dw:1350069792525:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350069861584:dw
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
as long as you have infinity as limits ... just relax .. they all are of same type of improper integral. probably you are confused with improper integral of second kind.
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350070134924:dwmaybe it is because it should have stated the following limits, I think I see a typo from the source
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
the second kind appears when you have singularity in domain.dw:1350070237179:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1350070363244:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
now I see the connection, it has to be establish  no wonder you made the statement earlier about it not being improper
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
dw:1350070434570:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
ok I thinkg I got it, it was the set up that threw me off. I think I understand the solution better now. Thanks
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.3
try watching this http://www.youtube.com/watch?v=KhwQKE_tld0
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
ok thanks, I can use all the help
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
Thanks, I enjoyed that lecture.
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.