line contains points (2, -2) and (-4, 1). Another line graphed in the same coordinate plane contains points (1, 2) and (-3, 4). Based on the slopes of these lines, are they parallel, perpendicular or neither?

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line contains points (2, -2) and (-4, 1). Another line graphed in the same coordinate plane contains points (1, 2) and (-3, 4). Based on the slopes of these lines, are they parallel, perpendicular or neither?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Ok so first we have to the slope of both lines
Do you remember the formula?
y2-y1/x-x1

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Other answers:

\( (2,-2)=(x_1,y_1)\) \((-4,1)=(x_2,y_2)\)
Parallel
\( \large {1-(-2) \over -4-(2)}=\frac{3}{6}=\frac{1}{2}\)
ughhh its -1/2 i forgot the negative
Parellel?
Try to find the slope of the second line Use the same process
I got parellel
Yes the lines are parallel since tehy both have the same slope but like i am assuming you have to solve it not just say its parallel

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