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vf321
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Can the sum of any two altitudes of a triangle be smaller than one of its legs?
 2 years ago
 2 years ago
vf321 Group Title
Can the sum of any two altitudes of a triangle be smaller than one of its legs?
 2 years ago
 2 years ago

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CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
I don't think so, but I'm not sure yet what the easiest proof of that would be.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.0
I'm sure the triangle inequality will be in there somewhere, and maybe, since altitudes form right angles, Pythagorean theorem will be useful.
 2 years ago

AnimalAin Group TitleBest ResponseYou've already chosen the best response.1
Consider an extremely obtuse isosceles triangle. With sides a,a, and b, angles theta (small), theta, and pi  2 theta. The two greater altitudes are b sin theta, so to meet the specification of the problem, 2bsin theta < b implies sin theta less than 1/2. Plenty of angles meet that specification.
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.0
@AnimalAin That works, thanks. You proved that for triangle ABC, \(a > h_b + h_c\) for some \(a\). What if I asked you to prove that the following: \(b>h_b+h_c\) for some \(b\)?
 2 years ago

AnimalAin Group TitleBest ResponseYou've already chosen the best response.1
Use the same method, assume b < a/2, and work the inequality similarly. The angles will be smaller, but it can be done.
 2 years ago
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