Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Can someone explain why
An = (2^n)/[3^(n+1)]
has a limit of 0. I'm missing something algebraically, I guess.
 one year ago
 one year ago
Can someone explain why An = (2^n)/[3^(n+1)] has a limit of 0. I'm missing something algebraically, I guess.
 one year ago
 one year ago

This Question is Closed

sevenshadedBest ResponseYou've already chosen the best response.0
as n goes to infinity?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
What gets bigger faster, 2^n or 3^n?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
So you'll get a number very very very large on the bottom sooner than you get one on the top, so it'll approach (something)/∞ before ∞/(something) or ∞/∞.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
There are more rigorous mathematical ways to show that, but do you understand the reasoning?
 one year ago

sevenshadedBest ResponseYou've already chosen the best response.0
I see. I mean, I understand it conceptually. Just not sure how I "show" that when I'm writing things out. "infinity/infinity" for work shown?
 one year ago

sevenshadedBest ResponseYou've already chosen the best response.0
And if it is infinity over infinity, then how would that converge to 0?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.0
Are you familiar with calculus derivatives and L'Hopital's rule?
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.