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Determine whether the series is convergent or divergent. If it is convergent, find its sum.
Problem inside.
 one year ago
 one year ago
Determine whether the series is convergent or divergent. If it is convergent, find its sum. Problem inside.
 one year ago
 one year ago

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sevenshadedBest ResponseYou've already chosen the best response.0
\[\sum_{2}^{\infty} \frac{ k^{2} }{ k^{2}1}\]
 one year ago

sevenshadedBest ResponseYou've already chosen the best response.0
Actually, that should be k = 2 under the summation.
 one year ago

sevenshadedBest ResponseYou've already chosen the best response.0
Basically, I know that the answer converges, but I don't know why. I would think that if the numerator was infinity squared and the denominator was infinity squared minus one, that the numerator was approaching infinity at a faster rate, thus making it diverge because it could just get bigger and bigger. But I guess that's incorrect reasoning.
 one year ago

sevenshadedBest ResponseYou've already chosen the best response.0
Secondly, I'm trying to put it into Ar ^ n format to begin to find the sum. I tried using k^2 times (k^2  1) ^1 but I'm not sure if that's correct either.
 one year ago
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