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anonymous
 3 years ago
Determine whether the series is convergent or divergent. If it is convergent, find its sum.
Problem inside.
anonymous
 3 years ago
Determine whether the series is convergent or divergent. If it is convergent, find its sum. Problem inside.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{2}^{\infty} \frac{ k^{2} }{ k^{2}1}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Actually, that should be k = 2 under the summation.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Basically, I know that the answer converges, but I don't know why. I would think that if the numerator was infinity squared and the denominator was infinity squared minus one, that the numerator was approaching infinity at a faster rate, thus making it diverge because it could just get bigger and bigger. But I guess that's incorrect reasoning.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Secondly, I'm trying to put it into Ar ^ n format to begin to find the sum. I tried using k^2 times (k^2  1) ^1 but I'm not sure if that's correct either.
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