v.s
Differentiate.
F(y) =
1/(y^2 −3/y^4)(y + 5y^3)



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v.s
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F(y) = (1/y^2 −3/y^4)(y + 5y^3)

v.s
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use product rule?

VeritasVosLiberabit
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is this the correct equation?

v.s
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no

v.s
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F(y) = (1/y^2 −3/y^4)(y + 5y^3)

VeritasVosLiberabit
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\[F(y)=\frac{ 1 }{ y ^{2} \frac{ 3 }{ y ^{4} }}(y+5y ^{3})\]

VeritasVosLiberabit
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how does this one look?

v.s
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\[\frac{ 1 }{ y ^{2} }\frac{ 3 }{ y ^{4} }(y+5y ^{3})\]


v.s
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both fractions r in a bracket together

VeritasVosLiberabit
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\[F(y)=y ^{2}3y ^{4}(y+5y ^{3})\]
I would first rewrite it like this and then use the product/chainrule.

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okkay

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(y^−2−3y^−4)(y+5y3)

VeritasVosLiberabit
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\[F'(y)=2y ^{3}3y ^{4}(1+15y ^{2})+(y+5y ^{3})(12y ^{5})\]

VeritasVosLiberabit
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you can combine like terms in order to get a simplified answer

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thanks man
