## kiamonstaa what is the simplified form of x^2+6x+8/4-x^2 one year ago one year ago

1. satellite73

factor the numerator as $$(x+2)(x+4)$$ and the denominator as $$(2-x)(2+x)$$ then cancel the common factor

2. dietrich_harmon

3. x^2 + 6x + 8 / 4 - x^2? x+6x+2-x 6x+2 is your final answer.

3. satellite73

i am fairly sure the question is $\frac{x^2+6x+8}{4-x^2}$

4. kiamonstaa

im confused. would yu do distributive property for the top?

5. satellite73

well yes, you would use the distributive property to factor. you get $\frac{x^2+6x+8}{4-x^2}=\frac{(x+4)(x+2)}{(2-x)(2+x)}$ $=\frac{(x+4)\cancel{(x+2)}}{(2-x)\cancel{(2+x)}}=\frac{x+4}{2-x}$

6. kiamonstaa

omg. okay thanks.

7. satellite73

yw