Ruchi.
how to find log of log50/15?
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Ruchi.
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@lgbasallote @Hero @Libniz @TranceNova
hartnn
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is it (log 50)/15 or log(50/15) ?
Ruchi.
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\[\log_{50/15} \]
hartnn
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that has no meaning
the base is 50/15 ?
vipul92
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convert 50=5*10
and 15=5*3
so now =log10/3
=log10-log3
=1-log3
vipul92
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now it easily solving i think
hartnn
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lol, no...and she also needs to find log of that.....
Ruchi.
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waht shold be the value of = -2.303*2*298*log50/15 ?
now please elaboarate.
vipul92
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i think -717.69
hartnn
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can't u use calculator ?
u can find log (50/15) = log(10/3) using calcy
vipul92
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@ruchi k now can i ask 1 que.?
hartnn
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* log(10/3) using calcy ONLY, not manually
Ruchi.
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yah @vipul92
hey @hartnn btw the value is -1436 calories.
gaara438125
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@hartnn it's ok @vipul92 is just posting answers to people's posts and usually posting wrong answers
hartnn
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-1436 is double the value of expression that u wrote
vipul92
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hey @gaara you don't know how to multiply and subtract two no. and said that i m wrong
Ruchi.
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excuse me.! @vipul92 this place is for posting questings and answering them, so please don't do useless talks here.
that would go against the code of conduct!
thanks!
vipul92
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k as u wish
hartnn
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using calculator -2.303*2*298*log(50/15) = -717.697
-1436 is double of that
Ruchi.
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sorry to everone the question is something like this : -2.303*2*2*298*log(50/15) =
hartnn
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-2.303*2*2*298*log(50/15)=-1436 using calculator
Ruchi.
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hey i'm asking that how u hav find log in this question
hartnn
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doesn't your calculator have the option to calculate log?
if not then u can simplify log(50/15) = log (10/3) = log 10 -log 3 =1-log 3
and u need to know log 3 = 0.477
Ruchi.
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in xamination calculator r nt preferred.
hartnn
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then i think, u need to remember atleast these 2 :
log 2 = 0.301, log 3 = 0.477
Ruchi.
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hey hw to find log of 20/5?
Hero
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I'm still trying to figure out the notation. What country are you from?
Hero
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You can interpret that in different ways:
\[\log_{20}{(5)}\]
\[\log_{10}(20/5)\]
\[\log_{5}(20)\]
Hero
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If it's
\[\log_{10}(20/5) = \log_{10}(4)\] , then it is relatively easy.
Hero
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But if it's something other than that, then idk
Hero
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@ruchi.
Hero
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If you want help, you will need to clarify what the notation is.
Hero
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Okay, so if it is what I think it is, then
log(20/5) = 2 log(2) = .602
Ruchi.
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hey hw u fing it?
hartnn
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\(\log (20/5)=log 4 = log (2^2)=2log2 \\ \text{from the property of log that :} \\ \huge logx^n=nlogx\)
and as i mentioned, u should remember log 2 =0.301