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Ruchi.

how to find log of log50/15?

  • one year ago
  • one year ago

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  1. Ruchi.
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    @lgbasallote @Hero @Libniz @TranceNova

    • one year ago
  2. hartnn
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    is it (log 50)/15 or log(50/15) ?

    • one year ago
  3. Ruchi.
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    \[\log_{50/15} \]

    • one year ago
  4. hartnn
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    that has no meaning the base is 50/15 ?

    • one year ago
  5. vipul92
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    convert 50=5*10 and 15=5*3 so now =log10/3 =log10-log3 =1-log3

    • one year ago
  6. vipul92
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    now it easily solving i think

    • one year ago
  7. hartnn
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    lol, no...and she also needs to find log of that.....

    • one year ago
  8. Ruchi.
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    waht shold be the value of = -2.303*2*298*log50/15 ? now please elaboarate.

    • one year ago
  9. vipul92
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    i think -717.69

    • one year ago
  10. hartnn
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    can't u use calculator ? u can find log (50/15) = log(10/3) using calcy

    • one year ago
  11. vipul92
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    @ruchi k now can i ask 1 que.?

    • one year ago
  12. hartnn
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    * log(10/3) using calcy ONLY, not manually

    • one year ago
  13. Ruchi.
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    yah @vipul92 hey @hartnn btw the value is -1436 calories.

    • one year ago
  14. gaara438125
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    @hartnn it's ok @vipul92 is just posting answers to people's posts and usually posting wrong answers

    • one year ago
  15. hartnn
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    -1436 is double the value of expression that u wrote

    • one year ago
  16. vipul92
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    hey @gaara you don't know how to multiply and subtract two no. and said that i m wrong

    • one year ago
  17. Ruchi.
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    excuse me.! @vipul92 this place is for posting questings and answering them, so please don't do useless talks here. that would go against the code of conduct! thanks!

    • one year ago
  18. vipul92
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    k as u wish

    • one year ago
  19. hartnn
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    using calculator -2.303*2*298*log(50/15) = -717.697 -1436 is double of that

    • one year ago
  20. Ruchi.
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    sorry to everone the question is something like this : -2.303*2*2*298*log(50/15) =

    • one year ago
  21. hartnn
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    -2.303*2*2*298*log(50/15)=-1436 using calculator

    • one year ago
  22. Ruchi.
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    hey i'm asking that how u hav find log in this question

    • one year ago
  23. hartnn
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    doesn't your calculator have the option to calculate log? if not then u can simplify log(50/15) = log (10/3) = log 10 -log 3 =1-log 3 and u need to know log 3 = 0.477

    • one year ago
  24. Ruchi.
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    in xamination calculator r nt preferred.

    • one year ago
  25. hartnn
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    then i think, u need to remember atleast these 2 : log 2 = 0.301, log 3 = 0.477

    • one year ago
  26. Ruchi.
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    hey hw to find log of 20/5?

    • one year ago
  27. Hero
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    I'm still trying to figure out the notation. What country are you from?

    • one year ago
  28. Hero
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    You can interpret that in different ways: \[\log_{20}{(5)}\] \[\log_{10}(20/5)\] \[\log_{5}(20)\]

    • one year ago
  29. Hero
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    If it's \[\log_{10}(20/5) = \log_{10}(4)\] , then it is relatively easy.

    • one year ago
  30. Hero
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    But if it's something other than that, then idk

    • one year ago
  31. Hero
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    @ruchi.

    • one year ago
  32. Hero
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    If you want help, you will need to clarify what the notation is.

    • one year ago
  33. Hero
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    Okay, so if it is what I think it is, then log(20/5) = 2 log(2) = .602

    • one year ago
  34. Ruchi.
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    hey hw u fing it?

    • one year ago
  35. hartnn
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    \(\log (20/5)=log 4 = log (2^2)=2log2 \\ \text{from the property of log that :} \\ \huge logx^n=nlogx\) and as i mentioned, u should remember log 2 =0.301

    • one year ago
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