how to find log of log50/15?

- anonymous

how to find log of log50/15?

- schrodinger

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- anonymous

- hartnn

is it (log 50)/15 or log(50/15) ?

- anonymous

\[\log_{50/15} \]

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## More answers

- hartnn

that has no meaning
the base is 50/15 ?

- anonymous

convert 50=5*10
and 15=5*3
so now =log10/3
=log10-log3
=1-log3

- anonymous

now it easily solving i think

- hartnn

lol, no...and she also needs to find log of that.....

- anonymous

waht shold be the value of = -2.303*2*298*log50/15 ?
now please elaboarate.

- anonymous

i think -717.69

- hartnn

can't u use calculator ?
u can find log (50/15) = log(10/3) using calcy

- anonymous

@ruchi k now can i ask 1 que.?

- hartnn

* log(10/3) using calcy ONLY, not manually

- hartnn

-1436 is double the value of expression that u wrote

- anonymous

hey @gaara you don't know how to multiply and subtract two no. and said that i m wrong

- anonymous

excuse me.! @vipul92 this place is for posting questings and answering them, so please don't do useless talks here.
that would go against the code of conduct!
thanks!

- anonymous

k as u wish

- hartnn

using calculator -2.303*2*298*log(50/15) = -717.697
-1436 is double of that

- anonymous

sorry to everone the question is something like this : -2.303*2*2*298*log(50/15) =

- hartnn

-2.303*2*2*298*log(50/15)=-1436 using calculator

- anonymous

hey i'm asking that how u hav find log in this question

- hartnn

doesn't your calculator have the option to calculate log?
if not then u can simplify log(50/15) = log (10/3) = log 10 -log 3 =1-log 3
and u need to know log 3 = 0.477

- anonymous

in xamination calculator r nt preferred.

- hartnn

then i think, u need to remember atleast these 2 :
log 2 = 0.301, log 3 = 0.477

- anonymous

hey hw to find log of 20/5?

- Hero

I'm still trying to figure out the notation. What country are you from?

- Hero

You can interpret that in different ways:
\[\log_{20}{(5)}\]
\[\log_{10}(20/5)\]
\[\log_{5}(20)\]

- Hero

If it's
\[\log_{10}(20/5) = \log_{10}(4)\] , then it is relatively easy.

- Hero

But if it's something other than that, then idk

- Hero

- Hero

If you want help, you will need to clarify what the notation is.

- Hero

Okay, so if it is what I think it is, then
log(20/5) = 2 log(2) = .602

- anonymous

hey hw u fing it?

- hartnn

\(\log (20/5)=log 4 = log (2^2)=2log2 \\ \text{from the property of log that :} \\ \huge logx^n=nlogx\)
and as i mentioned, u should remember log 2 =0.301

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