## Ruchi. 2 years ago how to find log of log50/15?

1. Ruchi.

@lgbasallote @Hero @Libniz @TranceNova

2. hartnn

is it (log 50)/15 or log(50/15) ?

3. Ruchi.

$\log_{50/15}$

4. hartnn

that has no meaning the base is 50/15 ?

5. vipul92

convert 50=5*10 and 15=5*3 so now =log10/3 =log10-log3 =1-log3

6. vipul92

now it easily solving i think

7. hartnn

lol, no...and she also needs to find log of that.....

8. Ruchi.

waht shold be the value of = -2.303*2*298*log50/15 ? now please elaboarate.

9. vipul92

i think -717.69

10. hartnn

can't u use calculator ? u can find log (50/15) = log(10/3) using calcy

11. vipul92

@ruchi k now can i ask 1 que.?

12. hartnn

* log(10/3) using calcy ONLY, not manually

13. Ruchi.

yah @vipul92 hey @hartnn btw the value is -1436 calories.

14. gaara438125

@hartnn it's ok @vipul92 is just posting answers to people's posts and usually posting wrong answers

15. hartnn

-1436 is double the value of expression that u wrote

16. vipul92

hey @gaara you don't know how to multiply and subtract two no. and said that i m wrong

17. Ruchi.

excuse me.! @vipul92 this place is for posting questings and answering them, so please don't do useless talks here. that would go against the code of conduct! thanks!

18. vipul92

k as u wish

19. hartnn

using calculator -2.303*2*298*log(50/15) = -717.697 -1436 is double of that

20. Ruchi.

sorry to everone the question is something like this : -2.303*2*2*298*log(50/15) =

21. hartnn

-2.303*2*2*298*log(50/15)=-1436 using calculator

22. Ruchi.

23. hartnn

doesn't your calculator have the option to calculate log? if not then u can simplify log(50/15) = log (10/3) = log 10 -log 3 =1-log 3 and u need to know log 3 = 0.477

24. Ruchi.

in xamination calculator r nt preferred.

25. hartnn

then i think, u need to remember atleast these 2 : log 2 = 0.301, log 3 = 0.477

26. Ruchi.

hey hw to find log of 20/5?

27. Hero

I'm still trying to figure out the notation. What country are you from?

28. Hero

You can interpret that in different ways: $\log_{20}{(5)}$ $\log_{10}(20/5)$ $\log_{5}(20)$

29. Hero

If it's $\log_{10}(20/5) = \log_{10}(4)$ , then it is relatively easy.

30. Hero

But if it's something other than that, then idk

31. Hero

@ruchi.

32. Hero

If you want help, you will need to clarify what the notation is.

33. Hero

Okay, so if it is what I think it is, then log(20/5) = 2 log(2) = .602

34. Ruchi.

hey hw u fing it?

35. hartnn

$$\log (20/5)=log 4 = log (2^2)=2log2 \\ \text{from the property of log that :} \\ \huge logx^n=nlogx$$ and as i mentioned, u should remember log 2 =0.301