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Ruchi.

  • 3 years ago

how to find log of log50/15?

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  1. Ruchi.
    • 3 years ago
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    @lgbasallote @Hero @Libniz @TranceNova

  2. hartnn
    • 3 years ago
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    is it (log 50)/15 or log(50/15) ?

  3. Ruchi.
    • 3 years ago
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    \[\log_{50/15} \]

  4. hartnn
    • 3 years ago
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    that has no meaning the base is 50/15 ?

  5. vipul92
    • 3 years ago
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    convert 50=5*10 and 15=5*3 so now =log10/3 =log10-log3 =1-log3

  6. vipul92
    • 3 years ago
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    now it easily solving i think

  7. hartnn
    • 3 years ago
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    lol, no...and she also needs to find log of that.....

  8. Ruchi.
    • 3 years ago
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    waht shold be the value of = -2.303*2*298*log50/15 ? now please elaboarate.

  9. vipul92
    • 3 years ago
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    i think -717.69

  10. hartnn
    • 3 years ago
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    can't u use calculator ? u can find log (50/15) = log(10/3) using calcy

  11. vipul92
    • 3 years ago
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    @ruchi k now can i ask 1 que.?

  12. hartnn
    • 3 years ago
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    * log(10/3) using calcy ONLY, not manually

  13. Ruchi.
    • 3 years ago
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    yah @vipul92 hey @hartnn btw the value is -1436 calories.

  14. gaara438125
    • 3 years ago
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    @hartnn it's ok @vipul92 is just posting answers to people's posts and usually posting wrong answers

  15. hartnn
    • 3 years ago
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    -1436 is double the value of expression that u wrote

  16. vipul92
    • 3 years ago
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    hey @gaara you don't know how to multiply and subtract two no. and said that i m wrong

  17. Ruchi.
    • 3 years ago
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    excuse me.! @vipul92 this place is for posting questings and answering them, so please don't do useless talks here. that would go against the code of conduct! thanks!

  18. vipul92
    • 3 years ago
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    k as u wish

  19. hartnn
    • 3 years ago
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    using calculator -2.303*2*298*log(50/15) = -717.697 -1436 is double of that

  20. Ruchi.
    • 3 years ago
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    sorry to everone the question is something like this : -2.303*2*2*298*log(50/15) =

  21. hartnn
    • 3 years ago
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    -2.303*2*2*298*log(50/15)=-1436 using calculator

  22. Ruchi.
    • 3 years ago
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    hey i'm asking that how u hav find log in this question

  23. hartnn
    • 3 years ago
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    doesn't your calculator have the option to calculate log? if not then u can simplify log(50/15) = log (10/3) = log 10 -log 3 =1-log 3 and u need to know log 3 = 0.477

  24. Ruchi.
    • 3 years ago
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    in xamination calculator r nt preferred.

  25. hartnn
    • 3 years ago
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    then i think, u need to remember atleast these 2 : log 2 = 0.301, log 3 = 0.477

  26. Ruchi.
    • 3 years ago
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    hey hw to find log of 20/5?

  27. Hero
    • 3 years ago
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    I'm still trying to figure out the notation. What country are you from?

  28. Hero
    • 3 years ago
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    You can interpret that in different ways: \[\log_{20}{(5)}\] \[\log_{10}(20/5)\] \[\log_{5}(20)\]

  29. Hero
    • 3 years ago
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    If it's \[\log_{10}(20/5) = \log_{10}(4)\] , then it is relatively easy.

  30. Hero
    • 3 years ago
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    But if it's something other than that, then idk

  31. Hero
    • 3 years ago
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    @ruchi.

  32. Hero
    • 3 years ago
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    If you want help, you will need to clarify what the notation is.

  33. Hero
    • 3 years ago
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    Okay, so if it is what I think it is, then log(20/5) = 2 log(2) = .602

  34. Ruchi.
    • 3 years ago
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    hey hw u fing it?

  35. hartnn
    • 3 years ago
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    \(\log (20/5)=log 4 = log (2^2)=2log2 \\ \text{from the property of log that :} \\ \huge logx^n=nlogx\) and as i mentioned, u should remember log 2 =0.301

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