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A particle of mass 4m explodes into 3 pieces of masses m,m,2m. The equal masses move along X & Y axes with velocities 4m/s & 6m/s respectively. Find the magnitude of velocity the heavier mass (Choices Under root 17,2 x under root 13,under root 13 or under root 13/2 m/s
 one year ago
 one year ago
A particle of mass 4m explodes into 3 pieces of masses m,m,2m. The equal masses move along X & Y axes with velocities 4m/s & 6m/s respectively. Find the magnitude of velocity the heavier mass (Choices Under root 17,2 x under root 13,under root 13 or under root 13/2 m/s
 one year ago
 one year ago

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CoolsectorBest ResponseYou've already chosen the best response.0
dw:1350120916624:dw since the momentum of the system was zero at the beginning after the explode it remains zreo. now we have for the two masses : speed = sqrt(6^2+4^2) = sqrt(52) = 2sqrt(13) so the magnitude of the momentum of the two masses is m*2sqrt(13) this should be equal to 2m * V where V is the magnitude of the velocity of the larger mass 2m*V = m * 2sqrt(13) V = sqrt(13)
 one year ago

haridas_mandalBest ResponseYou've already chosen the best response.0
I fail to understand the logic " since the momentum of the system was zero at the beginning after the explode it remains zero"Can this be elaborated? Many thanks for the answer.. .
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
conservation of momentum .. no external forces acted upon the system so the total momentum has not changed
 one year ago
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