Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
haridas_mandal
Group Title
A particle of mass 4m explodes into 3 pieces of masses m,m,2m. The equal masses move along X & Y axes with velocities 4m/s & 6m/s respectively. Find the magnitude of velocity the heavier mass (Choices Under root 17,2 x under root 13,under root 13 or under root 13/2 m/s
 one year ago
 one year ago
haridas_mandal Group Title
A particle of mass 4m explodes into 3 pieces of masses m,m,2m. The equal masses move along X & Y axes with velocities 4m/s & 6m/s respectively. Find the magnitude of velocity the heavier mass (Choices Under root 17,2 x under root 13,under root 13 or under root 13/2 m/s
 one year ago
 one year ago

This Question is Closed

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
dw:1350120916624:dw since the momentum of the system was zero at the beginning after the explode it remains zreo. now we have for the two masses : speed = sqrt(6^2+4^2) = sqrt(52) = 2sqrt(13) so the magnitude of the momentum of the two masses is m*2sqrt(13) this should be equal to 2m * V where V is the magnitude of the velocity of the larger mass 2m*V = m * 2sqrt(13) V = sqrt(13)
 one year ago

haridas_mandal Group TitleBest ResponseYou've already chosen the best response.0
I fail to understand the logic " since the momentum of the system was zero at the beginning after the explode it remains zero"Can this be elaborated? Many thanks for the answer.. .
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.0
conservation of momentum .. no external forces acted upon the system so the total momentum has not changed
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.