Timtime
Find the amplitude and the period of q(x) = -sin (π/2 x).
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Timtime
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i got Amplitude = -1; Period = π/2
henryrodriguez713
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y="a"sinx
Amplitude= \[\left| a \right|\]
So, it should be 1 still. but what does happen to the graph is a flip
AravindG
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1 is amplitude
akash123
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period will be 4
henryrodriguez713
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|dw:1350111153230:dw|
henryrodriguez713
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For the period: let b be a positive real number. The period of y=a sin bx is given by
\[Period = \frac{ 2π }{ b }\]
\[\frac{ 2π }{π/2x }\]
just multiply by the reciprocal, |dw:1350111516421:dw|
henryrodriguez713
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This also goes for y=cosx
y=a sin bx & y=a cos bx