anonymous
  • anonymous
Find the amplitude and the period of q(x) = -sin (π/2 x).
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i got Amplitude = -1; Period = π/2
anonymous
  • anonymous
y="a"sinx Amplitude= \[\left| a \right|\] So, it should be 1 still. but what does happen to the graph is a flip
AravindG
  • AravindG
1 is amplitude

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anonymous
  • anonymous
period will be 4
anonymous
  • anonymous
|dw:1350111153230:dw|
anonymous
  • anonymous
For the period: let b be a positive real number. The period of y=a sin bx is given by \[Period = \frac{ 2π }{ b }\] \[\frac{ 2π }{π/2x }\] just multiply by the reciprocal, |dw:1350111516421:dw|
anonymous
  • anonymous
This also goes for y=cosx y=a sin bx & y=a cos bx

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