## anonymous 4 years ago Find the amplitude and the period of q(x) = -sin (π/2 x).

1. anonymous

i got Amplitude = -1; Period = π/2

2. anonymous

y="a"sinx Amplitude= $\left| a \right|$ So, it should be 1 still. but what does happen to the graph is a flip

3. AravindG

1 is amplitude

4. anonymous

period will be 4

5. anonymous

|dw:1350111153230:dw|

6. anonymous

For the period: let b be a positive real number. The period of y=a sin bx is given by $Period = \frac{ 2π }{ b }$ $\frac{ 2π }{π/2x }$ just multiply by the reciprocal, |dw:1350111516421:dw|

7. anonymous

This also goes for y=cosx y=a sin bx & y=a cos bx