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Timtime

  • 3 years ago

Find the amplitude and the period of q(x) = -sin (π/2 x).

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  1. Timtime
    • 3 years ago
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    i got Amplitude = -1; Period = π/2

  2. henryrodriguez713
    • 3 years ago
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    y="a"sinx Amplitude= \[\left| a \right|\] So, it should be 1 still. but what does happen to the graph is a flip

  3. AravindG
    • 3 years ago
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    1 is amplitude

  4. akash123
    • 3 years ago
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    period will be 4

  5. henryrodriguez713
    • 3 years ago
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    |dw:1350111153230:dw|

  6. henryrodriguez713
    • 3 years ago
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    For the period: let b be a positive real number. The period of y=a sin bx is given by \[Period = \frac{ 2π }{ b }\] \[\frac{ 2π }{π/2x }\] just multiply by the reciprocal, |dw:1350111516421:dw|

  7. henryrodriguez713
    • 3 years ago
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    This also goes for y=cosx y=a sin bx & y=a cos bx

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