## Ruchi. 2 years ago for the reaction c(graphite)+1/2o2=co at 298k and 1 atm ,H=-26416cal.if the molar vol. of graphite is 0.0053litre,calculate E?

1. hba

Yes Ruchi

2. Ruchi.

wait

3. Ruchi.

for the reaction \[c(graphite)+1/2o2=co\] at 298k and 1 atm ,H=-26416cal.if the molar vol. of graphite is 0.0053litre,calculate E?

4. Ruchi.

@hba @rambo2210

5. Ruchi.

@timo86

6. Ruchi.

@hitten101 @.Sam.

7. Ruchi.

@SinginDaCalc2Blues

8. SinginDaCalc2Blues

oh no...not hba again! haha

9. hba

Hello :)

10. SinginDaCalc2Blues

What is the question Ruchi?

11. hba

Are You Blind ?

12. hba

for the reaction c(graphite)+1/2o2=co at 298k and 1 atm ,H=-26416cal.if the molar vol. of graphite is 0.0053litre,calculate E?

13. SinginDaCalc2Blues

Nope...not blind...just wanted you to do the dirty work for me hba! sucker! haha

14. SinginDaCalc2Blues

Because I know you can't resit putting me down!

15. Ruchi.

hey hlp me out

16. SinginDaCalc2Blues

Hey Ruchi, what book do you use?

17. hba

Stop Crying Girl

18. SinginDaCalc2Blues

do you have to have energy in Calories, Kilocalories, Joules, or Kilojoules?

19. SinginDaCalc2Blues

ARE YOU STILL HERE?

20. hba

In Cal

21. SinginDaCalc2Blues

okay, well if you see this, as far as I can gather, the question looks like it is asking how much heat(E) is evolved from the reaction of carbon and o2. tHE -26416 cal is the Hrxn (Heat of the reaction). There is only 1 mole of carbon, and the molar mass of carbon is 12.01grams... so we have 1 mol C= 12.01g and 1 mol C: -26416 cal (from the reaction) so set up this equation: (1 mol C/12.01 g C) x (-26416 cal/1 mol C) = -2199.5cal I think this is correct.

22. SinginDaCalc2Blues

The logic seems correct as the energy given off is negative, as it should be for an exothermic combustion reaction, and it is much smaller than your Heat of reaction...I think this is correct...hope that helps!

23. SinginDaCalc2Blues

bye hba!!! haha :o)~

24. hba

Bye :)

25. Ruchi.

@TuringTest @sauravshakya hlp me out