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Ruchi. Group Title

for the reaction c(graphite)+1/2o2=co at 298k and 1 atm ,H=-26416cal.if the molar vol. of graphite is 0.0053litre,calculate E?

  • one year ago
  • one year ago

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  1. hba Group Title
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    Yes Ruchi

    • one year ago
  2. Ruchi. Group Title
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    wait

    • one year ago
  3. Ruchi. Group Title
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    for the reaction \[c(graphite)+1/2o2=co\] at 298k and 1 atm ,H=-26416cal.if the molar vol. of graphite is 0.0053litre,calculate E?

    • one year ago
  4. Ruchi. Group Title
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    @hba @rambo2210

    • one year ago
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    @timo86

    • one year ago
  6. Ruchi. Group Title
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    @hitten101 @.Sam.

    • one year ago
  7. Ruchi. Group Title
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    @SinginDaCalc2Blues

    • one year ago
  8. SinginDaCalc2Blues Group Title
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    oh no...not hba again! haha

    • one year ago
  9. hba Group Title
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    Hello :)

    • one year ago
  10. SinginDaCalc2Blues Group Title
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    What is the question Ruchi?

    • one year ago
  11. hba Group Title
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    Are You Blind ?

    • one year ago
  12. hba Group Title
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    for the reaction c(graphite)+1/2o2=co at 298k and 1 atm ,H=-26416cal.if the molar vol. of graphite is 0.0053litre,calculate E?

    • one year ago
  13. SinginDaCalc2Blues Group Title
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    Nope...not blind...just wanted you to do the dirty work for me hba! sucker! haha

    • one year ago
  14. SinginDaCalc2Blues Group Title
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    Because I know you can't resit putting me down!

    • one year ago
  15. Ruchi. Group Title
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    hey hlp me out

    • one year ago
  16. SinginDaCalc2Blues Group Title
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    Hey Ruchi, what book do you use?

    • one year ago
  17. hba Group Title
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    Stop Crying Girl

    • one year ago
  18. SinginDaCalc2Blues Group Title
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    do you have to have energy in Calories, Kilocalories, Joules, or Kilojoules?

    • one year ago
  19. SinginDaCalc2Blues Group Title
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    ARE YOU STILL HERE?

    • one year ago
  20. hba Group Title
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    In Cal

    • one year ago
  21. SinginDaCalc2Blues Group Title
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    okay, well if you see this, as far as I can gather, the question looks like it is asking how much heat(E) is evolved from the reaction of carbon and o2. tHE -26416 cal is the Hrxn (Heat of the reaction). There is only 1 mole of carbon, and the molar mass of carbon is 12.01grams... so we have 1 mol C= 12.01g and 1 mol C: -26416 cal (from the reaction) so set up this equation: (1 mol C/12.01 g C) x (-26416 cal/1 mol C) = -2199.5cal I think this is correct.

    • one year ago
  22. SinginDaCalc2Blues Group Title
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    The logic seems correct as the energy given off is negative, as it should be for an exothermic combustion reaction, and it is much smaller than your Heat of reaction...I think this is correct...hope that helps!

    • one year ago
  23. SinginDaCalc2Blues Group Title
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    bye hba!!! haha :o)~

    • one year ago
  24. hba Group Title
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    Bye :)

    • one year ago
  25. Ruchi. Group Title
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    @TuringTest @sauravshakya hlp me out

    • one year ago
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