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for the reaction \[c(graphite)+1/2o2=co\] at 298k and 1 atm ,H=-26416cal.if the molar vol. of graphite is 0.0053litre,calculate E?
oh no...not hba again! haha
What is the question Ruchi?
Are You Blind ?
for the reaction c(graphite)+1/2o2=co at 298k and 1 atm ,H=-26416cal.if the molar vol. of graphite is 0.0053litre,calculate E?
Nope...not blind...just wanted you to do the dirty work for me hba! sucker! haha
Because I know you can't resit putting me down!
hey hlp me out
Hey Ruchi, what book do you use?
Stop Crying Girl
do you have to have energy in Calories, Kilocalories, Joules, or Kilojoules?
ARE YOU STILL HERE?
okay, well if you see this, as far as I can gather, the question looks like it is asking how much heat(E) is evolved from the reaction of carbon and o2. tHE -26416 cal is the Hrxn (Heat of the reaction). There is only 1 mole of carbon, and the molar mass of carbon is 12.01grams... so we have 1 mol C= 12.01g and 1 mol C: -26416 cal (from the reaction) so set up this equation: (1 mol C/12.01 g C) x (-26416 cal/1 mol C) = -2199.5cal I think this is correct.
The logic seems correct as the energy given off is negative, as it should be for an exothermic combustion reaction, and it is much smaller than your Heat of reaction...I think this is correct...hope that helps!
bye hba!!! haha :o)~
@TuringTest @sauravshakya hlp me out