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shubhamsrg
Group Title
in the figure,
BD = CD
BE= DE
AP=PD
and, DG//CF
find ratio of areas of triangle ADH to ABC.
 one year ago
 one year ago
shubhamsrg Group Title
in the figure, BD = CD BE= DE AP=PD and, DG//CF find ratio of areas of triangle ADH to ABC.
 one year ago
 one year ago

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shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
dw:1350127616986:dw
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
looks like the other one....
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Just saying, it reminds me of te //gram question (with the other 2 sides missing)
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
so my opinion : area triangle ADH = (area triangle ABC)/4  area triangle DHE ????
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
yep..that'd be right sir..
 one year ago

NewbieCarrot Group TitleBest ResponseYou've already chosen the best response.0
My opinion is use AD as base, find the relationship between B and H in triangle ABD.
 one year ago

NewbieCarrot Group TitleBest ResponseYou've already chosen the best response.0
dw:1350131794371:dw S=S'
 one year ago

NewbieCarrot Group TitleBest ResponseYou've already chosen the best response.0
so S' would be 1/6 of ABE=1/6 * A/4=A/24 So AHD=A/4A/24=5A/24
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
will you please elaborate the solution ?
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
that's excellent..thank you again @sauravshakya :)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
welcome
 one year ago
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