shubhamsrg
in the figure,
BD = CD
BE= DE
AP=PD
and, DG//CF
find ratio of areas of triangle ADH to ABC.



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shubhamsrg
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dw:1350127616986:dw

estudier
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looks like the other one....

shubhamsrg
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??

estudier
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Just saying, it reminds me of te //gram question (with the other 2 sides missing)

shubhamsrg
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hmm..

jhonyy9
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so my opinion :
area triangle ADH = (area triangle ABC)/4  area triangle DHE
????

shubhamsrg
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yep..that'd be right sir..

NewbieCarrot
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My opinion is use AD as base, find the relationship between B and H in triangle ABD.

NewbieCarrot
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dw:1350131794371:dw
S=S'

NewbieCarrot
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so S' would be 1/6 of ABE=1/6 * A/4=A/24
So AHD=A/4A/24=5A/24

shubhamsrg
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will you please elaborate the solution ?

sauravshakya
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shubhamsrg
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that's excellent..thank you again @sauravshakya :)

sauravshakya
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welcome