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shubhamsrg
Group Title
in the figure,
BD = CD
BE= DE
AP=PD
and, DG//CF
find ratio of areas of triangle ADH to ABC.
 2 years ago
 2 years ago
shubhamsrg Group Title
in the figure, BD = CD BE= DE AP=PD and, DG//CF find ratio of areas of triangle ADH to ABC.
 2 years ago
 2 years ago

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shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
dw:1350127616986:dw
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
looks like the other one....
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Just saying, it reminds me of te //gram question (with the other 2 sides missing)
 2 years ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.0
so my opinion : area triangle ADH = (area triangle ABC)/4  area triangle DHE ????
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
yep..that'd be right sir..
 2 years ago

NewbieCarrot Group TitleBest ResponseYou've already chosen the best response.0
My opinion is use AD as base, find the relationship between B and H in triangle ABD.
 2 years ago

NewbieCarrot Group TitleBest ResponseYou've already chosen the best response.0
dw:1350131794371:dw S=S'
 2 years ago

NewbieCarrot Group TitleBest ResponseYou've already chosen the best response.0
so S' would be 1/6 of ABE=1/6 * A/4=A/24 So AHD=A/4A/24=5A/24
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
will you please elaborate the solution ?
 2 years ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
that's excellent..thank you again @sauravshakya :)
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
welcome
 2 years ago
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