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shubhamsrg

  • 3 years ago

in the figure, BD = CD BE= DE AP=PD and, DG//CF find ratio of areas of triangle ADH to ABC.

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  1. shubhamsrg
    • 3 years ago
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    |dw:1350127616986:dw|

  2. estudier
    • 3 years ago
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    looks like the other one....

  3. shubhamsrg
    • 3 years ago
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    ??

  4. estudier
    • 3 years ago
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    Just saying, it reminds me of te //gram question (with the other 2 sides missing)

  5. shubhamsrg
    • 3 years ago
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    hmm..

  6. jhonyy9
    • 3 years ago
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    so my opinion : area triangle ADH = (area triangle ABC)/4 - area triangle DHE ????

  7. shubhamsrg
    • 3 years ago
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    yep..that'd be right sir..

  8. NewbieCarrot
    • 3 years ago
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    My opinion is use AD as base, find the relationship between B and H in triangle ABD.

  9. NewbieCarrot
    • 3 years ago
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    |dw:1350131794371:dw| S=S'

  10. NewbieCarrot
    • 3 years ago
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    so S' would be 1/6 of ABE=1/6 * A/4=A/24 So AHD=A/4-A/24=5A/24

  11. shubhamsrg
    • 3 years ago
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    will you please elaborate the solution ?

  12. sauravshakya
    • 3 years ago
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  13. shubhamsrg
    • 3 years ago
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    that's excellent..thank you again @sauravshakya :)

  14. sauravshakya
    • 3 years ago
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    welcome

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