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shubhamsrg Group Title

in the figure, BD = CD BE= DE AP=PD and, DG//CF find ratio of areas of triangle ADH to ABC.

  • 2 years ago
  • 2 years ago

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  1. shubhamsrg Group Title
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    |dw:1350127616986:dw|

    • 2 years ago
  2. estudier Group Title
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    looks like the other one....

    • 2 years ago
  3. shubhamsrg Group Title
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    ??

    • 2 years ago
  4. estudier Group Title
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    Just saying, it reminds me of te //gram question (with the other 2 sides missing)

    • 2 years ago
  5. shubhamsrg Group Title
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    hmm..

    • 2 years ago
  6. jhonyy9 Group Title
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    so my opinion : area triangle ADH = (area triangle ABC)/4 - area triangle DHE ????

    • 2 years ago
  7. shubhamsrg Group Title
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    yep..that'd be right sir..

    • 2 years ago
  8. NewbieCarrot Group Title
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    My opinion is use AD as base, find the relationship between B and H in triangle ABD.

    • 2 years ago
  9. NewbieCarrot Group Title
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    |dw:1350131794371:dw| S=S'

    • 2 years ago
  10. NewbieCarrot Group Title
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    so S' would be 1/6 of ABE=1/6 * A/4=A/24 So AHD=A/4-A/24=5A/24

    • 2 years ago
  11. shubhamsrg Group Title
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    will you please elaborate the solution ?

    • 2 years ago
  12. sauravshakya Group Title
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    • 2 years ago
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  13. shubhamsrg Group Title
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    that's excellent..thank you again @sauravshakya :)

    • 2 years ago
  14. sauravshakya Group Title
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    welcome

    • 2 years ago
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