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in the figure, BD = CD BE= DE AP=PD and, DG//CF find ratio of areas of triangle ADH to ABC.

Mathematics
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|dw:1350127616986:dw|
looks like the other one....
??

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Other answers:

Just saying, it reminds me of te //gram question (with the other 2 sides missing)
hmm..
so my opinion : area triangle ADH = (area triangle ABC)/4 - area triangle DHE ????
yep..that'd be right sir..
My opinion is use AD as base, find the relationship between B and H in triangle ABD.
|dw:1350131794371:dw| S=S'
so S' would be 1/6 of ABE=1/6 * A/4=A/24 So AHD=A/4-A/24=5A/24
will you please elaborate the solution ?
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that's excellent..thank you again @sauravshakya :)
welcome

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