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u can use quad formula here

What happens then when i take the square root of -7/4+6i?

\[\sqrt{-\frac{ 7 }{4 }+6i}\]

\[Z = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }\]

\[i^2 = -1\]

\[\frac{ \-1+6i \pm \sqrt{(1-6i)^{2}+4(7*9i)} }{ 4}\]

But 1-6i squared is 1-12i-36 so i still get the root of i

can't u use calculator ?

We aren't allowed to use calculators at all at my university

can u convert complex number to polar form manually ?

Yepp, maybe it's easier to solve in Euler form?

not tried, ever

Ok, I'll try it out it might just work :)

u know the answer ? if not wanna know ?

I know it, z=1+5i and z=-2+i

yeah, even i did see wolf, all 3 methods....each required sqrt of (-7/4+6i)

Ohh, that's clever! Will try it out!

trust me, I did not figure this idea out first.

By the way are you guys at MIT allowed to use calculators to there kind of problems?

Open Book seems at least more genuine, it reflects the worklife better, than our memorization tests.

your discriminant simplifies to -7+24i
the square root is reasonably straight forward