• anonymous
Solve the complex equation: $(2+i)z ^{2}+(8-11i)z-5-25i=0$ I started to isolate the first term and got: $z ^{2}+\frac{ 8-11i }{ 2+i }z + \frac{ -5-25i }{ 2+1 } = 0$ $z ^{2}+(1-6i)z-(7+9i)=0$ How should i continue from here? I can't use the quadratic formula, right? So i guess i need to factorize, but how?
Mathematics

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