Solve the complex equation: \[(2+i)z ^{2}+(8-11i)z-5-25i=0\]
I started to isolate the first term and got:
\[z ^{2}+\frac{ 8-11i }{ 2+i }z + \frac{ -5-25i }{ 2+1 } = 0\]
\[z ^{2}+(1-6i)z-(7+9i)=0\]
How should i continue from here? I can't use the quadratic formula, right? So i guess i need to factorize, but how?

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u can use quad formula here

What happens then when i take the square root of -7/4+6i?

\[\sqrt{-\frac{ 7 }{4 }+6i}\]

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