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marktj
 3 years ago
How do you synthetically divide (4x^37x^211x+50/(4x+5)?
marktj
 3 years ago
How do you synthetically divide (4x^37x^211x+50/(4x+5)?

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darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.1first you need to extract the value of x on the denominator 4x + 5 = 0 4x = 5 x = 5/4

Nory
 3 years ago
Best ResponseYou've already chosen the best response.0Now write it like long division, except eliminate the x's and just write the coefficcients like you write synthetic division.

jaersyn
 3 years ago
Best ResponseYou've already chosen the best response.0can you draw the set up real quick?

darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.1remember to follow the level of their degree...

darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.1@jaersyn yep..it's like that..

darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.1wait..you forgot to write their signs @jaersyn

jaersyn
 3 years ago
Best ResponseYou've already chosen the best response.0i'm not even op, just trynna learn lol

darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.15/4  4 7 11 50

jaersyn
 3 years ago
Best ResponseYou've already chosen the best response.0then you drop the 4, do (5/4)*4 and put that under 7 and subtract or add?

darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.1depends on the sign..if it is negative you subtract.. if positive, you add..

darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.1if both of them possess the same sign then you add them then copy the sign..

jaersyn
 3 years ago
Best ResponseYou've already chosen the best response.05/4 * 12 = 15 so 11 + 15 = 4

darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.1you got it right...

jaersyn
 3 years ago
Best ResponseYou've already chosen the best response.0gotcha thanks for your help

darkprince14
 3 years ago
Best ResponseYou've already chosen the best response.1no prob...glad to be of help:)
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