Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

H5P1 ZERO-OFFSET AMPLIFIER In many amplifiers, we use dual power supplies so we can obtain a 0V offset at the output, that is, the DC operating point at the output is 0V. An example amplifier circuit that can achieve this is shown below. In this circuit, VS+=1.0V, VS−=−1.0V, and the MOSFET parameters are K=1 mAV2 and VT=0.5V. what formulas do i need

MIT 6.002 Circuits and Electronics, Spring 2007
See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

tell me the formula
-0.5, 8000, 0.093
if correct please click best response

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

H5P2 Source Follower Large Signal ....question 4
i m not gettin the lab part of homework 5..........can u help me
Run Transient Analysis. From plot, measure linear operating region: upper is 0.6V and lower is 1.16 V (approx). For Gain: Run Tran Analysis, measure output peak to peak= 1.94V (approx) and input peak to peak is 0.2V. So Gain = 1.94/0.2 = 9.7 For last part, there is a distortion. We know from Part 1 that the largest signal input that can be amplified without distortion is 1.16-0.6 = 0.56V, so amplitude is 0.56/2 = 0.28V

Not the answer you are looking for?

Search for more explanations.

Ask your own question