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WhiiteRussian
 2 years ago
Best ResponseYou've already chosen the best response.0It would just be 0

WhiiteRussian
 2 years ago
Best ResponseYou've already chosen the best response.0Using L'hopitals rule

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.1note that\[\sin(\frac{1}{x^4+y^4})\]is a limited function between 1 and 1 whatever x,y are so we have a limited function multiplying zero (because y>0) and\[\lim_{(x,y) \rightarrow(0,0)} y \ \sin(\frac{1}{x^4+y^4})=\lim_{y \rightarrow 0} \times\lim_{(x,y) \rightarrow(0,0)} \sin(\frac{1}{x^4+y^4})=0\times \text{limited}=0\]make sense???
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