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Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f(t) = \frac{ \sec(t) }{ 3 } + \sec(t)\]
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
this is the question ?
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
or it's 3+sec(t) in the denominator ?
 one year ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
in the denominator
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f(t)=\frac{ \sec(t) }{ 3 + \sec(t) }\]
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
like this ?
 one year ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.0
In this case, use quotient rule.
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
grr mistake : all over again
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f'(t) = \frac{ \sec(t)' * (3+\sec(t))  (3+\sec(t))' * \sec(t) }{ (3+\sec(t))^2 }\]
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f'(t) = \frac{ \tan(t)\sec(t) * (3+\sec(t))  \tan(t)\sec(t) * \sec(t) }{ (3+\sec(t))^2 }\]
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f'(t) = \frac{ 3\tan(t)\sec(t) }{ (3+\sec(t))^2 }\]
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
nothing much more to do ..
 one year ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
so you expand and simplify?
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
the final answer ? you can expand the (3+sec(t))^2 but it's not really important ..
 one year ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
i used the quotient rule in order to find the derivative as you can see the procedure
 one year ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
okaay thank you :)
 one year ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
i got the aanswer wrong
 one year ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
i'm doing this online quiz and wen i put in the answer it was wrong
 one year ago
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