anonymous
  • anonymous
Differentiate. f(θ) = sec θ/3 + sec θ
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[f(t) = \frac{ \sec(t) }{ 3 } + \sec(t)\]
anonymous
  • anonymous
this is the question ?
anonymous
  • anonymous
or it's 3+sec(t) in the denominator ?

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anonymous
  • anonymous
yeaaa
anonymous
  • anonymous
in the denominator
anonymous
  • anonymous
\[f(t)=\frac{ \sec(t) }{ 3 + \sec(t) }\]
anonymous
  • anonymous
like this ?
anonymous
  • anonymous
yes
anonymous
  • anonymous
In this case, use quotient rule.
anonymous
  • anonymous
grr mistake :| all over again
anonymous
  • anonymous
\[f'(t) = \frac{ \sec(t)' * (3+\sec(t)) - (3+\sec(t))' * \sec(t) }{ (3+\sec(t))^2 }\]
anonymous
  • anonymous
\[f'(t) = \frac{ \tan(t)\sec(t) * (3+\sec(t)) - \tan(t)\sec(t) * \sec(t) }{ (3+\sec(t))^2 }\]
anonymous
  • anonymous
\[f'(t) = \frac{ 3\tan(t)\sec(t) }{ (3+\sec(t))^2 }\]
anonymous
  • anonymous
nothing much more to do ..
anonymous
  • anonymous
so you expand and simplify?
anonymous
  • anonymous
the final answer ? you can expand the (3+sec(t))^2 but it's not really important ..
anonymous
  • anonymous
i used the quotient rule in order to find the derivative as you can see the procedure
anonymous
  • anonymous
okaay thank you :)
anonymous
  • anonymous
yw
anonymous
  • anonymous
i got the aanswer wrong
anonymous
  • anonymous
i'm doing this online quiz and wen i put in the answer it was wrong

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