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Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f(t) = \frac{ \sec(t) }{ 3 } + \sec(t)\]
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
this is the question ?
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
or it's 3+sec(t) in the denominator ?
 2 years ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
in the denominator
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f(t)=\frac{ \sec(t) }{ 3 + \sec(t) }\]
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
like this ?
 2 years ago

micahwood50 Group TitleBest ResponseYou've already chosen the best response.0
In this case, use quotient rule.
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
grr mistake : all over again
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f'(t) = \frac{ \sec(t)' * (3+\sec(t))  (3+\sec(t))' * \sec(t) }{ (3+\sec(t))^2 }\]
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f'(t) = \frac{ \tan(t)\sec(t) * (3+\sec(t))  \tan(t)\sec(t) * \sec(t) }{ (3+\sec(t))^2 }\]
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
\[f'(t) = \frac{ 3\tan(t)\sec(t) }{ (3+\sec(t))^2 }\]
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
nothing much more to do ..
 2 years ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
so you expand and simplify?
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
the final answer ? you can expand the (3+sec(t))^2 but it's not really important ..
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
i used the quotient rule in order to find the derivative as you can see the procedure
 2 years ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
okaay thank you :)
 2 years ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
i got the aanswer wrong
 2 years ago

v.s Group TitleBest ResponseYou've already chosen the best response.0
i'm doing this online quiz and wen i put in the answer it was wrong
 2 years ago
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