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(b) Find the position, velocity, and acceleration of the mass at time t = 5π/6.
x(t) = 8 cos t
v(t) = 8sint
a(t) = 8cost
x(5π/6)=
v(5π/6)=
a(5π/6) =
 one year ago
 one year ago
(b) Find the position, velocity, and acceleration of the mass at time t = 5π/6. x(t) = 8 cos t v(t) = 8sint a(t) = 8cost x(5π/6)= v(5π/6)= a(5π/6) =
 one year ago
 one year ago

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v.sBest ResponseYou've already chosen the best response.0
i get decimals for the answers, i'm just wonder how i would answer it on a test
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
cos(5pi/6) = sqrt(3)/2 sin(5pi/6) = 0.5
 one year ago

phiBest ResponseYou've already chosen the best response.1
you should memorize sin,cos and tan of 0,30,45, 60 and 90 degrees you should know how to change between radians and degrees radians *180/pi or degrees*pi/180 you should know how to figure out the signs depending on which quadrant you are in for sin, cos, tan
 one year ago

v.sBest ResponseYou've already chosen the best response.0
okaay so i have to answer in radiants
 one year ago

phiBest ResponseYou've already chosen the best response.1
if I were doing this, I would say 5pi/6 is the same as 30 degrees in the 2nd quadrant. sin will be +, cos 
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.0
That is correct for 8cos(5pi / 6)
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.0
So you have the concept, just apply it to the rest.
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
v(5π/6)=4 .. right
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.0
a(5pi/6) right as well
 one year ago

v.sBest ResponseYou've already chosen the best response.0
thank you guys learned alot
 one year ago

phiBest ResponseYou've already chosen the best response.1
I don't know that it really helps me memorize sin of these angles, it is interesting: angle sin(angle) 0 \(\frac{\sqrt{0}}{2}\) 30 \(\frac{\sqrt{1}}{2}\) 45 \(\frac{\sqrt{2}}{2}\) 60 \(\frac{\sqrt{3}}{2}\) 90 \(\frac{\sqrt{4}}{2}\)
 one year ago
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