anonymous
  • anonymous
(b) Find the position, velocity, and acceleration of the mass at time t = 5π/6. x(t) = 8 cos t v(t) = -8sint a(t) = -8cost x(5π/6)= v(5π/6)= a(5π/6) =
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
i get decimals for the answers, i'm just wonder how i would answer it on a test
anonymous
  • anonymous
cos(5pi/6) = -sqrt(3)/2 sin(5pi/6) = 0.5
anonymous
  • anonymous
helps ?

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phi
  • phi
you should memorize sin,cos and tan of 0,30,45, 60 and 90 degrees you should know how to change between radians and degrees radians *180/pi or degrees*pi/180 you should know how to figure out the signs depending on which quadrant you are in for sin, cos, tan
cwrw238
  • cwrw238
a = -8 cos (5pi/6)
anonymous
  • anonymous
okaay so i have to answer in radiants
anonymous
  • anonymous
http://upload.wikimedia.org/wikipedia/commons/thumb/4/4c/Unit_circle_angles_color.svg/300px-Unit_circle_angles_color.svg.png
phi
  • phi
if I were doing this, I would say 5pi/6 is the same as 30 degrees in the 2nd quadrant. sin will be +, cos -
anonymous
  • anonymous
x(5pi/6)=-4sqroot3
anonymous
  • anonymous
That is correct for 8cos(5pi / 6)
anonymous
  • anonymous
okaay
anonymous
  • anonymous
So you have the concept, just apply it to the rest.
anonymous
  • anonymous
v(t)=-4
anonymous
  • anonymous
a(t)=4sqroot3
anonymous
  • anonymous
v(5π/6)=-4 .. right
anonymous
  • anonymous
a(5pi/6) right as well
anonymous
  • anonymous
thank you guys learned alot
phi
  • phi
I don't know that it really helps me memorize sin of these angles, it is interesting: angle sin(angle) 0 \(\frac{\sqrt{0}}{2}\) 30 \(\frac{\sqrt{1}}{2}\) 45 \(\frac{\sqrt{2}}{2}\) 60 \(\frac{\sqrt{3}}{2}\) 90 \(\frac{\sqrt{4}}{2}\)
anonymous
  • anonymous
thank you

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