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anonymous
 3 years ago
(b) Find the position, velocity, and acceleration of the mass at time t = 5π/6.
x(t) = 8 cos t
v(t) = 8sint
a(t) = 8cost
x(5π/6)=
v(5π/6)=
a(5π/6) =
anonymous
 3 years ago
(b) Find the position, velocity, and acceleration of the mass at time t = 5π/6. x(t) = 8 cos t v(t) = 8sint a(t) = 8cost x(5π/6)= v(5π/6)= a(5π/6) =

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i get decimals for the answers, i'm just wonder how i would answer it on a test

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cos(5pi/6) = sqrt(3)/2 sin(5pi/6) = 0.5

phi
 3 years ago
Best ResponseYou've already chosen the best response.1you should memorize sin,cos and tan of 0,30,45, 60 and 90 degrees you should know how to change between radians and degrees radians *180/pi or degrees*pi/180 you should know how to figure out the signs depending on which quadrant you are in for sin, cos, tan

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okaay so i have to answer in radiants

phi
 3 years ago
Best ResponseYou've already chosen the best response.1if I were doing this, I would say 5pi/6 is the same as 30 degrees in the 2nd quadrant. sin will be +, cos 

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That is correct for 8cos(5pi / 6)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So you have the concept, just apply it to the rest.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a(5pi/6) right as well

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you guys learned alot

phi
 3 years ago
Best ResponseYou've already chosen the best response.1I don't know that it really helps me memorize sin of these angles, it is interesting: angle sin(angle) 0 \(\frac{\sqrt{0}}{2}\) 30 \(\frac{\sqrt{1}}{2}\) 45 \(\frac{\sqrt{2}}{2}\) 60 \(\frac{\sqrt{3}}{2}\) 90 \(\frac{\sqrt{4}}{2}\)
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