3psilon
  • 3psilon
How to tell what i^33 is . I remember doing this in algebra 2 but I forgot how to
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
i^4 = 1 33 = 4x8+1 => i^33=i^1=i
anonymous
  • anonymous
i^1=i i^2=-1 i^3=-i i^4=1 That's the pattern, so look for anay number smaller than the given or the given and check if it's divisible by 4. In this case as rahul91 wrote 4*8+1=33 so you know that i^32 equals 1 and i^1 equals i so the answer is 1*i
anonymous
  • anonymous
Any exponentnummber divisible by four equals 1 by the pattern above

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

3psilon
  • 3psilon
Thank you @frx very helpful :)
anonymous
  • anonymous
np

Looking for something else?

Not the answer you are looking for? Search for more explanations.