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3psilon

  • 3 years ago

How to tell what i^33 is . I remember doing this in algebra 2 but I forgot how to

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  1. rahul91
    • 3 years ago
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    i^4 = 1 33 = 4x8+1 => i^33=i^1=i

  2. frx
    • 3 years ago
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    i^1=i i^2=-1 i^3=-i i^4=1 That's the pattern, so look for anay number smaller than the given or the given and check if it's divisible by 4. In this case as rahul91 wrote 4*8+1=33 so you know that i^32 equals 1 and i^1 equals i so the answer is 1*i

  3. frx
    • 3 years ago
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    Any exponentnummber divisible by four equals 1 by the pattern above

  4. 3psilon
    • 3 years ago
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    Thank you @frx very helpful :)

  5. frx
    • 3 years ago
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    np

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