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 2 years ago
I need to find the derivative using the chain and quotient rules of F(x)= ((3x2)^3)/((x3)^5). I just don't know when to stop doing chain rule and start the quotient
 2 years ago
I need to find the derivative using the chain and quotient rules of F(x)= ((3x2)^3)/((x3)^5). I just don't know when to stop doing chain rule and start the quotient

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frx
 2 years ago
Best ResponseYou've already chosen the best response.3Start by thinking of the quotient rule, it's (f'(x)g(x)f(x)g'(x))/(g(x))^2

frx
 2 years ago
Best ResponseYou've already chosen the best response.3Then you just replace the derivitives using the chainrule

frx
 2 years ago
Best ResponseYou've already chosen the best response.3\[\frac{ f'(x)*(x3)^{5}  (3x2)^{3}g'(x) }{(x3)^{10} }\]

marytheshade
 2 years ago
Best ResponseYou've already chosen the best response.0don't you have to do the chain rule first? is it possible to derive the F(x) and g(x) equations without the chain rule?

frx
 2 years ago
Best ResponseYou've already chosen the best response.3You have to do the chainrule when replacing the derivitives in the function i wrote above

frx
 2 years ago
Best ResponseYou've already chosen the best response.3I think it's easier to start of writing it as above

marytheshade
 2 years ago
Best ResponseYou've already chosen the best response.0okay so I did the chain rule and got F'(g(x))= 9(3x2)^2 (top function deriv) and g'(x)= 5(x3)^4 (denominator deriv) so do I plug in those values or do I have to take the chain rule further?

frx
 2 years ago
Best ResponseYou've already chosen the best response.3You just put them in as you counted them, the derivitive of f(x) is f'(x) and it's what you're looking for according to the quotientrule.

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.0You've done with derivative u' and v' Plug them into the formula ( u'v  uv' ) / v²
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