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v.s
 3 years ago
Find the limit.
lim 3 − 3 tan x/sin x − cos x
x→π/4
v.s
 3 years ago
Find the limit. lim 3 − 3 tan x/sin x − cos x x→π/4

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zordoloom
 3 years ago
Best ResponseYou've already chosen the best response.0Could you write out how this looks. the division sign doesn't really indicate where the equation is divided.

zordoloom
 3 years ago
Best ResponseYou've already chosen the best response.0At least put parenthesis where they belong.

v.s
 3 years ago
Best ResponseYou've already chosen the best response.0lim (3 − 3 tan x)/(sin x − cos x) x→π/4

frx
 3 years ago
Best ResponseYou've already chosen the best response.0First try to just put in the value pi/4 and decide if the function is defined in that point

frx
 3 years ago
Best ResponseYou've already chosen the best response.0You see that sin pi/4 cos pi/4 equals zero so the function is undefined at pi/4 so what you want to do is to simplify the function

chrisplusian
 3 years ago
Best ResponseYou've already chosen the best response.0you can turn your denominator into\[(33(\frac{ cosx }{ sinx })\] then split the numerator into two different fractions\[\frac{ 3 }{ sinxcosx }  \frac{ \frac{ sinx }{ cosx } }{ sinxcosx }\]

chrisplusian
 3 years ago
Best ResponseYou've already chosen the best response.0sorry meant numerator

chrisplusian
 3 years ago
Best ResponseYou've already chosen the best response.0and that should have been three times sine over cosine sorry I am messing it up pretty bad

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 33\tan(x) }{ \sin(x)  \cos(x) } \times \frac{ \sin(x) +\cos(x) }{ \sin(x) +\cos(x) }\]

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 3\sin(x)  3\frac{ \sin^2(x) }{ \cos(x) } + 3\cos(x) 3\sin(x) }{ \sin^2(x) \cos^2(x) }\]

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{  3\frac{ \sin^2(x) }{ \cos(x) } + 3\cos(x) }{ \sin^2(x) \cos^2(x) }\]

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{  3\sin^2(x) + 3\cos^2(x) }{ \cos(x)[\sin^2(x) \cos^2(x)] } = \frac{ 3 }{ \cos(x) }\]

Coolsector
 3 years ago
Best ResponseYou've already chosen the best response.1which simplifies into 3sqrt(2)
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