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zordoloomBest ResponseYou've already chosen the best response.0
Could you write out how this looks. the division sign doesn't really indicate where the equation is divided.
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
At least put parenthesis where they belong.
 one year ago

v.sBest ResponseYou've already chosen the best response.0
lim (3 − 3 tan x)/(sin x − cos x) x→π/4
 one year ago

frxBest ResponseYou've already chosen the best response.0
First try to just put in the value pi/4 and decide if the function is defined in that point
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
you'll get 3sqrt(2)
 one year ago

frxBest ResponseYou've already chosen the best response.0
You see that sin pi/4 cos pi/4 equals zero so the function is undefined at pi/4 so what you want to do is to simplify the function
 one year ago

chrisplusianBest ResponseYou've already chosen the best response.0
you can turn your denominator into\[(33(\frac{ cosx }{ sinx })\] then split the numerator into two different fractions\[\frac{ 3 }{ sinxcosx }  \frac{ \frac{ sinx }{ cosx } }{ sinxcosx }\]
 one year ago

chrisplusianBest ResponseYou've already chosen the best response.0
sorry meant numerator
 one year ago

chrisplusianBest ResponseYou've already chosen the best response.0
and that should have been three times sine over cosine sorry I am messing it up pretty bad
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.1
\[\frac{ 33\tan(x) }{ \sin(x)  \cos(x) } \times \frac{ \sin(x) +\cos(x) }{ \sin(x) +\cos(x) }\]
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.1
\[\frac{ 3\sin(x)  3\frac{ \sin^2(x) }{ \cos(x) } + 3\cos(x) 3\sin(x) }{ \sin^2(x) \cos^2(x) }\]
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.1
\[\frac{  3\frac{ \sin^2(x) }{ \cos(x) } + 3\cos(x) }{ \sin^2(x) \cos^2(x) }\]
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.1
\[\frac{  3\sin^2(x) + 3\cos^2(x) }{ \cos(x)[\sin^2(x) \cos^2(x)] } = \frac{ 3 }{ \cos(x) }\]
 one year ago

CoolsectorBest ResponseYou've already chosen the best response.1
which simplifies into 3sqrt(2)
 one year ago
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