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v.s Group Title

Find the limit. lim 3 − 3 tan x/sin x − cos x x→π/4

  • 2 years ago
  • 2 years ago

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  1. zordoloom Group Title
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    Could you write out how this looks. the division sign doesn't really indicate where the equation is divided.

    • 2 years ago
  2. zordoloom Group Title
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    At least put parenthesis where they belong.

    • 2 years ago
  3. v.s Group Title
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    lim (3 − 3 tan x)/(sin x − cos x) x→π/4

    • 2 years ago
  4. frx Group Title
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    First try to just put in the value pi/4 and decide if the function is defined in that point

    • 2 years ago
  5. zordoloom Group Title
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    you'll get -3sqrt(2)

    • 2 years ago
  6. frx Group Title
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    You see that sin pi/4- cos pi/4 equals zero so the function is undefined at pi/4 so what you want to do is to simplify the function

    • 2 years ago
  7. v.s Group Title
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    okaaaaaaaaay thambi

    • 2 years ago
  8. v.s Group Title
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    how do i simplify this?

    • 2 years ago
  9. chrisplusian Group Title
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    you can turn your denominator into\[(3-3(\frac{ cosx }{ sinx })\] then split the numerator into two different fractions\[\frac{ 3 }{ sinx-cosx } - \frac{ \frac{ sinx }{ cosx } }{ sinx-cosx }\]

    • 2 years ago
  10. chrisplusian Group Title
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    sorry meant numerator

    • 2 years ago
  11. chrisplusian Group Title
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    and that should have been three times sine over cosine sorry I am messing it up pretty bad

    • 2 years ago
  12. v.s Group Title
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    loll itss okayy

    • 2 years ago
  13. v.s Group Title
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    i dont get the question

    • 2 years ago
  14. Coolsector Group Title
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    \[\frac{ 3-3\tan(x) }{ \sin(x) - \cos(x) } \times \frac{ \sin(x) +\cos(x) }{ \sin(x) +\cos(x) }\]

    • 2 years ago
  15. Coolsector Group Title
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    \[\frac{ 3\sin(x) - 3\frac{ \sin^2(x) }{ \cos(x) } + 3\cos(x) -3\sin(x) }{ \sin^2(x) -\cos^2(x) }\]

    • 2 years ago
  16. Coolsector Group Title
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    \[\frac{ - 3\frac{ \sin^2(x) }{ \cos(x) } + 3\cos(x) }{ \sin^2(x) -\cos^2(x) }\]

    • 2 years ago
  17. Coolsector Group Title
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    \[\frac{ - 3\sin^2(x) + 3\cos^2(x) }{ \cos(x)[\sin^2(x) -\cos^2(x)] } = \frac{ -3 }{ \cos(x) }\]

    • 2 years ago
  18. v.s Group Title
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    sorry i was busy

    • 2 years ago
  19. v.s Group Title
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    so i sub in pi/4

    • 2 years ago
  20. Coolsector Group Title
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    yes

    • 2 years ago
  21. v.s Group Title
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    -3/(1/sqroot2)

    • 2 years ago
  22. Coolsector Group Title
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    which simplifies into -3sqrt(2)

    • 2 years ago
  23. v.s Group Title
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    -sqroot2/3

    • 2 years ago
  24. Coolsector Group Title
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    no .. -3 * sqrt(2)

    • 2 years ago
  25. v.s Group Title
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    yeye

    • 2 years ago
  26. v.s Group Title
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    i gett it

    • 2 years ago
  27. Coolsector Group Title
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    \[-3\sqrt2\]

    • 2 years ago
  28. Coolsector Group Title
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    like this

    • 2 years ago
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