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reno15

  • 3 years ago

For questions 3–4, what is the value of x to the nearest tenth? 3. circle with radius X (1 point) 4.2 6.6 10.4 11.6 4. circle (1 point) 3.6 5.8 11.5 14.3

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  1. reno15
    • 3 years ago
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  2. reno15
    • 3 years ago
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  3. nubeer
    • 3 years ago
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    4. apply pythagoras theorem 6.5^2 = 3^2 + y ^2 solve and get value of y which will be y = 5.76 as i have found the half of the length , so x =2y x =11.5

  4. reno15
    • 3 years ago
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    okt thankyou!:)

  5. nubeer
    • 3 years ago
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    you're welcome.. u have to solve the other question by same way..

  6. FaisalAyaz
    • 3 years ago
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    nubeer the first question is not like the second.What about that question?

  7. nubeer
    • 3 years ago
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    its same.. u just have to find the hypotaneous .. which will be same as value of x

  8. FaisalAyaz
    • 3 years ago
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    but nubeer dear 3.6 and 11 are points.Not the magnitudes of lengths.so..?

  9. nubeer
    • 3 years ago
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    i dont think those are points .. those are magnitudes.. ..i dont think anywhere it states that those are maginitude.. if 11 would be a point it would also have another coordinate to find the magnitude.

  10. FaisalAyaz
    • 3 years ago
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    yes.I was taking them as a point and was confused that how to find the second coordinate.

  11. FaisalAyaz
    • 3 years ago
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    \[\sqrt{43} ans. solve \sqrt{43} by calculator i have nt dis time.\]

  12. nubeer
    • 3 years ago
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    well it's not point.. its magnitude bcos 11 is written clearing that its magnitude. and @reno15 no your answer is not correct.. let me tell u again Hyp ^2 = base ^2 + perpendicular ^2 in your 3rd question case base = 11/2 perp = 3.6 so hyp^2 = 5.5^2 + 3.6^2 hyp^2 = 43.21 hyp =6.57

  13. FaisalAyaz
    • 3 years ago
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    hmmm.well nubeer It's right!!!

  14. reno15
    • 3 years ago
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    thanx guyz!! :D

  15. nubeer
    • 3 years ago
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    you're welcome :)

  16. FaisalAyaz
    • 3 years ago
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    Most Welcome....

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