## reno15 Group Title For questions 3–4, what is the value of x to the nearest tenth? 3. circle with radius X (1 point) 4.2 6.6 10.4 11.6 4. circle (1 point) 3.6 5.8 11.5 14.3 one year ago one year ago

1. reno15 Group Title

2. reno15 Group Title

3. nubeer Group Title

4. apply pythagoras theorem 6.5^2 = 3^2 + y ^2 solve and get value of y which will be y = 5.76 as i have found the half of the length , so x =2y x =11.5

4. reno15 Group Title

okt thankyou!:)

5. nubeer Group Title

you're welcome.. u have to solve the other question by same way..

6. FaisalAyaz Group Title

nubeer the first question is not like the second.What about that question?

7. nubeer Group Title

its same.. u just have to find the hypotaneous .. which will be same as value of x

8. FaisalAyaz Group Title

but nubeer dear 3.6 and 11 are points.Not the magnitudes of lengths.so..?

9. nubeer Group Title

i dont think those are points .. those are magnitudes.. ..i dont think anywhere it states that those are maginitude.. if 11 would be a point it would also have another coordinate to find the magnitude.

10. FaisalAyaz Group Title

yes.I was taking them as a point and was confused that how to find the second coordinate.

11. FaisalAyaz Group Title

$\sqrt{43} ans. solve \sqrt{43} by calculator i have nt dis time.$

12. nubeer Group Title

well it's not point.. its magnitude bcos 11 is written clearing that its magnitude. and @reno15 no your answer is not correct.. let me tell u again Hyp ^2 = base ^2 + perpendicular ^2 in your 3rd question case base = 11/2 perp = 3.6 so hyp^2 = 5.5^2 + 3.6^2 hyp^2 = 43.21 hyp =6.57

13. FaisalAyaz Group Title

hmmm.well nubeer It's right!!!

14. reno15 Group Title

thanx guyz!! :D

15. nubeer Group Title

you're welcome :)

16. FaisalAyaz Group Title

Most Welcome....