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reno15
For questions 3–4, what is the value of x to the nearest tenth? 3. circle with radius X (1 point) 4.2 6.6 10.4 11.6 4. circle (1 point) 3.6 5.8 11.5 14.3
4. apply pythagoras theorem 6.5^2 = 3^2 + y ^2 solve and get value of y which will be y = 5.76 as i have found the half of the length , so x =2y x =11.5
you're welcome.. u have to solve the other question by same way..
nubeer the first question is not like the second.What about that question?
its same.. u just have to find the hypotaneous .. which will be same as value of x
but nubeer dear 3.6 and 11 are points.Not the magnitudes of lengths.so..?
i dont think those are points .. those are magnitudes.. ..i dont think anywhere it states that those are maginitude.. if 11 would be a point it would also have another coordinate to find the magnitude.
yes.I was taking them as a point and was confused that how to find the second coordinate.
\[\sqrt{43} ans. solve \sqrt{43} by calculator i have nt dis time.\]
well it's not point.. its magnitude bcos 11 is written clearing that its magnitude. and @reno15 no your answer is not correct.. let me tell u again Hyp ^2 = base ^2 + perpendicular ^2 in your 3rd question case base = 11/2 perp = 3.6 so hyp^2 = 5.5^2 + 3.6^2 hyp^2 = 43.21 hyp =6.57
hmmm.well nubeer It's right!!!