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reno15
Group Title
For questions 3–4, what is the value of x to the nearest tenth?
3.
circle with radius X (1 point)
4.2
6.6
10.4
11.6
4.
circle (1 point)
3.6
5.8
11.5
14.3
 one year ago
 one year ago
reno15 Group Title
For questions 3–4, what is the value of x to the nearest tenth? 3. circle with radius X (1 point) 4.2 6.6 10.4 11.6 4. circle (1 point) 3.6 5.8 11.5 14.3
 one year ago
 one year ago

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nubeer Group TitleBest ResponseYou've already chosen the best response.3
4. apply pythagoras theorem 6.5^2 = 3^2 + y ^2 solve and get value of y which will be y = 5.76 as i have found the half of the length , so x =2y x =11.5
 one year ago

reno15 Group TitleBest ResponseYou've already chosen the best response.0
okt thankyou!:)
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.3
you're welcome.. u have to solve the other question by same way..
 one year ago

FaisalAyaz Group TitleBest ResponseYou've already chosen the best response.0
nubeer the first question is not like the second.What about that question?
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.3
its same.. u just have to find the hypotaneous .. which will be same as value of x
 one year ago

FaisalAyaz Group TitleBest ResponseYou've already chosen the best response.0
but nubeer dear 3.6 and 11 are points.Not the magnitudes of lengths.so..?
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.3
i dont think those are points .. those are magnitudes.. ..i dont think anywhere it states that those are maginitude.. if 11 would be a point it would also have another coordinate to find the magnitude.
 one year ago

FaisalAyaz Group TitleBest ResponseYou've already chosen the best response.0
yes.I was taking them as a point and was confused that how to find the second coordinate.
 one year ago

FaisalAyaz Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{43} ans. solve \sqrt{43} by calculator i have nt dis time.\]
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.3
well it's not point.. its magnitude bcos 11 is written clearing that its magnitude. and @reno15 no your answer is not correct.. let me tell u again Hyp ^2 = base ^2 + perpendicular ^2 in your 3rd question case base = 11/2 perp = 3.6 so hyp^2 = 5.5^2 + 3.6^2 hyp^2 = 43.21 hyp =6.57
 one year ago

FaisalAyaz Group TitleBest ResponseYou've already chosen the best response.0
hmmm.well nubeer It's right!!!
 one year ago

reno15 Group TitleBest ResponseYou've already chosen the best response.0
thanx guyz!! :D
 one year ago

nubeer Group TitleBest ResponseYou've already chosen the best response.3
you're welcome :)
 one year ago

FaisalAyaz Group TitleBest ResponseYou've already chosen the best response.0
Most Welcome....
 one year ago
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