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phiBest ResponseYou've already chosen the best response.1
you could try using \[ (a+bi)^2 = 53i \] this means \[ a^2b^2 + 2abi = 5 3i\] equate real with real, and imag with imag. solve for a and b
 one year ago

livelaughlilzBest ResponseYou've already chosen the best response.0
by equate do you mean say a2^b2 = 5 and 2abi = 3i? as in set up two seperate equations?
 one year ago

FaisalAyazBest ResponseYou've already chosen the best response.0
\[\sqrt{53i} = \sqrt{5}  \sqrt{3i}\]
 one year ago

phiBest ResponseYou've already chosen the best response.1
a^2  b^2 = 5 and 2abi = 3i yes
 one year ago

livelaughlilzBest ResponseYou've already chosen the best response.0
@FaisalAyaz i don't think it does. \[\sqrt{a + b} \neq \sqrt{a}+\sqrt{b}\]
 one year ago

FaisalAyazBest ResponseYou've already chosen the best response.0
Yes.It's Wrong.I Forgot....sorry
 one year ago

livelaughlilzBest ResponseYou've already chosen the best response.0
@phi for the a^2  b^2 = 5 part i got a = +/ 3, and b = +/2 (by guess and check, i'm not sure how to do it algebraically) for the 2abi = 3i i got ab = 3/2 i'm slightly stuck. do i try and solve a system of equations now since i have two equations, or somehow plug the values back in, or what?
 one year ago

livelaughlilzBest ResponseYou've already chosen the best response.0
@phi i got 32i and 3+2i as my answers. is that right?
 one year ago

livelaughlilzBest ResponseYou've already chosen the best response.0
then is it wrong that a and b are (3, 2) or (3, 2)?
 one year ago

phiBest ResponseYou've already chosen the best response.1
I am getting some very ugly numbers for this problem. see http://www.wolframalpha.com/input/?i=%28sqrt%28+0.5%285%2Bsqrt%2834%29%29%293%2F%282*sqrt%28+0.5%285%2Bsqrt%2834%29%29%29%29*i%29%5E2 Are you sure you have the correct problem?
 one year ago

livelaughlilzBest ResponseYou've already chosen the best response.0
yes i just checked i have the right problem
 one year ago

phiBest ResponseYou've already chosen the best response.1
you can get the ugly result by saying 2ab= 3 b= 3/(2a) b^2 = 9/(4a^2) sub into a^2  b^2 =5 a^2  9/(4a^2) = 5 multiply by 4a^2 4a^4 20a^2 9 =0 or a^4 5a^2 9/4  0 let x= a^2, so you get a quadratic x^2  5x 9/4=0 use the quadratic formula to find x. then take the square root of x to find a then solve for b
 one year ago

livelaughlilzBest ResponseYou've already chosen the best response.0
what bout the plus or minus part? i have [5 +/ sqrt(34)]/[2]  b^2 = 5
 one year ago

phiBest ResponseYou've already chosen the best response.1
the ± give you different answers. (square roots will have 2 answers)
 one year ago

phiBest ResponseYou've already chosen the best response.1
first choose + and find the answers then 
 one year ago

livelaughlilzBest ResponseYou've already chosen the best response.0
okay. i have to go now. i might sign on later, after i work on the problem some more. thank you. bye.
 one year ago

phiBest ResponseYou've already chosen the best response.1
remember you can use wolfram to check your answers
 one year ago
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