marmar3000
Simplify (4x − 5)^2.
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FaisalAyaz
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(a+b)^2=a^2 + b^2 + 2ab
anonymous
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does that mean "multiply"? start with
\[(4x+5)(4x+5)\] and do four multiplications
FaisalAyaz
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(a-b)^2 = a^2 + b^2 -2ab
anonymous
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oops rather
\[(4x-5)(4x-5)\]
marmar3000
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thankss(:
anonymous
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do four multiplications, combine like terms, and then tell your teacher (gently) that there is nothing "simpler" about your result than there is in \((4x-5)^2\)
marmar3000
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is it 16x+25?
anonymous
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oh no! careful here
anonymous
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four multiplications i will write them out
anonymous
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\[(4x-5)(4x-5)=4x\times 4x-5\times 4x-5\times 4x+5\times 5\]
FaisalAyaz
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(4x-5)^2 = 16x^2 -40x +25.
marmar3000
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16x-40x+25?
anonymous
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then \(4x\times 4x=16x^2\)
\(-5\times 4x-5\times 4x=-20x-20x=-40x\)
\((-5)\times (-5)=25\) final answer is
\[16x^2-40x+25\]
FaisalAyaz
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now factorize it or solve by formula \[x=-b \pm \sqrt{b^{2}-4ac}/2a\]
FaisalAyaz
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no marmar it's 16x^2 - 40x +25.
not 16x
FaisalAyaz
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now use quadratic formula or apply factorization method.it's up to u
FaisalAyaz
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U got it marmar? just use formula (a-b)^2 = a^2 + b^2 -2ab.
then find x by factorization or quadratic formula.Simple!
marmar3000
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yea, thanks guys!