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ERoseM
 2 years ago
A ball is thrown upward from the top of a building 160 ft high with an initial velocity of 48 ft/sec.
Find the maximum height the ball reaches. Position Formula is 16t^2+48T+160
ERoseM
 2 years ago
A ball is thrown upward from the top of a building 160 ft high with an initial velocity of 48 ft/sec. Find the maximum height the ball reaches. Position Formula is 16t^2+48T+160

This Question is Closed

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1s = 16t²+48t +160 Vertex coordinate ( h, k) h = ...?

ERoseM
 2 years ago
Best ResponseYou've already chosen the best response.0I'm confused on what you mean?

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1Do you know what vertex is?

ERoseM
 2 years ago
Best ResponseYou've already chosen the best response.0Yeas, but s is the position function so it looks like this right?dw:1350177313835:dw

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, vertex point in this case is maximum point!

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1Do know how to find vertex coordinate?

ERoseM
 2 years ago
Best ResponseYou've already chosen the best response.0No, I guess not then, how should I go about doing that?
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