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A ball is thrown upward from the top of a building 160 ft high with an initial velocity of 48 ft/sec.
Find the maximum height the ball reaches. Position Formula is 16t^2+48T+160
 one year ago
 one year ago
A ball is thrown upward from the top of a building 160 ft high with an initial velocity of 48 ft/sec. Find the maximum height the ball reaches. Position Formula is 16t^2+48T+160
 one year ago
 one year ago

This Question is Closed

ChlorophyllBest ResponseYou've already chosen the best response.1
s = 16t²+48t +160 Vertex coordinate ( h, k) h = ...?
 one year ago

ERoseMBest ResponseYou've already chosen the best response.0
I'm confused on what you mean?
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
Do you know what vertex is?
 one year ago

ERoseMBest ResponseYou've already chosen the best response.0
Yeas, but s is the position function so it looks like this right?dw:1350177313835:dw
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
Yes, vertex point in this case is maximum point!
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
Do know how to find vertex coordinate?
 one year ago

ERoseMBest ResponseYou've already chosen the best response.0
No, I guess not then, how should I go about doing that?
 one year ago
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