A community for students.
Here's the question you clicked on:
 0 viewing
ERoseM
 3 years ago
A ball is thrown upward from the top of a building 160 ft high with an initial velocity of 48 ft/sec.
Find the maximum height the ball reaches. Position Formula is 16t^2+48T+160
ERoseM
 3 years ago
A ball is thrown upward from the top of a building 160 ft high with an initial velocity of 48 ft/sec. Find the maximum height the ball reaches. Position Formula is 16t^2+48T+160

This Question is Closed

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.1s = 16t²+48t +160 Vertex coordinate ( h, k) h = ...?

ERoseM
 3 years ago
Best ResponseYou've already chosen the best response.0I'm confused on what you mean?

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.1Do you know what vertex is?

ERoseM
 3 years ago
Best ResponseYou've already chosen the best response.0Yeas, but s is the position function so it looks like this right?dw:1350177313835:dw

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.1Yes, vertex point in this case is maximum point!

Chlorophyll
 3 years ago
Best ResponseYou've already chosen the best response.1Do know how to find vertex coordinate?

ERoseM
 3 years ago
Best ResponseYou've already chosen the best response.0No, I guess not then, how should I go about doing that?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.