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Tonks
Group Title
More fun:
0 = 0
=0+0+0+0+0+...
=(11)+(11)+(11)+(11)+...
=11+11+11+11+...
= 1+ 1 +1 + 1 +1 + 1 +1 +...
= 1 + (1+1) + (1+1) + (1+1) +...
= 1 + 0 + 0 + 0 + 0 + ...
= 1 + 0
= 1
Therefore 0 = 1, Q.E.D.
Where's the problem?
 one year ago
 one year ago
Tonks Group Title
More fun: 0 = 0 =0+0+0+0+0+... =(11)+(11)+(11)+(11)+... =11+11+11+11+... = 1+ 1 +1 + 1 +1 + 1 +1 +... = 1 + (1+1) + (1+1) + (1+1) +... = 1 + 0 + 0 + 0 + 0 + ... = 1 + 0 = 1 Therefore 0 = 1, Q.E.D. Where's the problem?
 one year ago
 one year ago

This Question is Closed

Tonks Group TitleBest ResponseYou've already chosen the best response.0
I don't need help, I just like to post fun things while I wait for other stuff. Can you find the problem in this reasoning? (there has to be a problem, or else all numbers equal each other and cease to have meaning!)
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
there will be 1 at last?
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
I am not sure that can done or not because we dont know how many how many terms are there in 0+0+0+0+0... Infinity is unreachable.
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
Sorry for typo
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
yep u r right !!!
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
Let there are n terms in 0+0+0+0+... Then Now, let 0=(11) Then (11)+(11)+... 11+11+11... Now this will have 2n terms........ and 2n will be even numbers. Now, 11+11+1... =1(11)(11)+... If u will group that like that. and to get 1 there must be odd number of terms But we know it has 2n terms which is even. Thus, it cannot be 1
 one year ago

zugzwang Group TitleBest ResponseYou've already chosen the best response.1
How about \[0 = \sum_{0}^{\infty}0\]is fine \[0=\sum_{0}^{\infty}(1  1)\]is fine But \[0 = 11+11+11... = \sum_{0}^{\infty}(1)^{n}\] is not fine ...?
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
\[(11)+(11)+(11)+(11)+... \ne1 + (1+1) + (1+1) + (1+1) +..\]Evidently. But why? http://en.wikipedia.org/wiki/Grandi's_series http://en.wikipedia.org/wiki/Eilenberg%E2%80%93Mazur_swindle
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
error is from line four to line five a term is missing =11+11+11+11+... = 1+ 1 +1 + 1 +1 + 1 +1 + 1 ...
 one year ago
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