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SephI
I need help with a venn diagram. Is anyone good at those?
At an auto show, a care dealer asked the first 10 visitors their ages and the kinds of cars they own. The venn diagram shows the details. |dw:1350207143022:dw| Based on the diagram, which of the following represents the ages of car owners in the set (N ∪ ~L) ∪(L ∩ M) {29, 31, 64} {29, 31, 45, 64,} {29, 31, 38, 42, 45, 64} {29, 31, 38, 42, 44, 45, 64}
N ∪ ~L That would be all of N, with exclusion to L, correct?
you need to label your circles, L, N, M
Based on the diagram, which of the following represents the ages of car owners in the set (N ∪ ~L) ∪(L ∩ M) {29, 31, 64} {29, 31, 45, 64,} {29, 31, 38, 42, 45, 64} {29, 31, 38, 42, 44, 45, 64
I think you diagrams are a little off... as there is a 38 in L and 38 in the intersection of M and N... |dw:1350207574575:dw|
but anyway isn't the union of N and ~L the same as the union of N and M excluding 38, 44.
I don't know. That's why I asked you guys...
Hartnn to save the day ;-; At an auto show, a care dealer asked the first 10 visitors their ages and the kinds of cars they own. The venn diagram shows the details. |dw:1350210016776:dw| Based on the diagram, which of the following represents the ages of car owners in the set (N ∪ ~L) ∪(L ∩ M) {29, 31, 64} {29, 31, 45, 64,} {29, 31, 38, 42, 45, 64} {29, 31, 38, 42, 44, 45, 64}
i didn't properly understand the question, where is that 38 ? can u plz post the screenshot of question?
I cannt post the screenshot question. I can't leave the tab. I have two computers. The 38 is grouped with the 42. Here, check this out. scroll down some: http://www.purplemath.com/modules/venndiag2.htm
what did u give that reference ? (N ∪ ~L) = all numbers except 38 (L ∩ M) =45 and their union will be all numbers except 38, which does not seem to be an option :\
Oh, okay. Can we go one step at a time, please c: (N ∪ ~L) would be all the numbers of M and L, with exclusion to L? So just all numbers in M?
OH WAIT! (N ∩ ~L) ∪(L ∩ M) <-----
~L = all number except those in L = {35,51,42,38,29,31,64} got this ?
(N ∩ ~L) This will be what N and L have in common?
~L = all number except those in L = {35,51,42,38,29,31,64} got this ?
Yes, so all numbers in common with N except L?
'so all numbers in common with N except L?' <--for what ? ok, since u get ~L= {35,51,42,38,29,31,64}, we already have N = {38,42,29,64,31,44} now just find common elements between these 2 sets to get (N ∩ ~L)
∩ = common elements = and
~L All numbers in the diagram except those in L N = all in L Now we just find the common elements, correct?
~L All numbers in the diagram except those in L<--\(\huge \color{red}{\checkmark}\) N = all in L<---?? NO
N =all elements in circle N
Oh okay! ~L= {35,51,42,38,29,31,64}, N = {38,42,29,64,31,44} {29, 31, 38, 42, 64} Correct?
\(\huge \color{red}{\checkmark}\)
{29, 31, 38, 42, 64} ∪ (L ∩ M Is that what we're left with?
(L ∩ M ) = common elements between L and M = ??
Ok. Give me a second. I have to go do something, I will be back in five minutes. Will you be on?
(L ∩ M ) = common elements between L and M = ??
{35, 38, 42, 45, 51} {38, 44, 45} {38, 45} Correct?
consider those 2 38's as different elements
Wait. I don't get why they're different elements?
because they are on different circles.....and final answer will remain same whether u consider 38 or not...but appropiate will be to NOT consider
{29, 31, 38, 42, 64} ∪ {45} Correct?
\(\huge \color{red}{\checkmark}\) and that equals ?
Now this means we put the numbers together, and cancel like terms?
cancel ? not totally, keep exactly 1 instance example {25,26,27}U{26,27,28}={25,26,27,28}
{29, 31, 38, 42, 64} ∪ {45} {29, 41, 38, 42, 45, 64} Correct?
\(\huge \color{red}{\checkmark}\)
How do you do the checkmark?