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estudierBest ResponseYou've already chosen the best response.0
dw:1350208678915:dw
 one year ago

estudierBest ResponseYou've already chosen the best response.0
A square, a point inside of it distances from 3 vertices as shown
 one year ago

estudierBest ResponseYou've already chosen the best response.0
This is for experimentX, who loves algebra..:)
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
haha ... you are kidding!!
 one year ago

estudierBest ResponseYou've already chosen the best response.0
It's not too hard..(it's still too early)
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
is that all info??
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
if we call ne side a then the area is \[A=a^2\]
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
and the side is less than 17
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
according to triangle equality
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
dw:1350209046775:dw
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[9^2=a^2+10^22(10)(a)\cos \theta\] \[762=10^2+a^22(a)(10)\cos (90\theta)\]
 one year ago

estudierBest ResponseYou've already chosen the best response.0
2 var 1 equation suggests simultaneous equations as the way to go....
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
i meant 7^2dw:1350176811646:dw
 one year ago

estudierBest ResponseYou've already chosen the best response.0
JonasK is on the right track
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
what about using the area rule
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
probably @hartnn method would work out too ... since they are all independent equations.
 one year ago

estudierBest ResponseYou've already chosen the best response.0
"what about using the area rule" U just want to get rid of the 90 bit and then you can get rid of theta
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
still that's quite a bit of algebra since they are all non linear equations ... let's try something better.
 one year ago

estudierBest ResponseYou've already chosen the best response.0
Cos of angle opposite 7 is sin theta....
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
dw:1350209708034:dw
 one year ago

estudierBest ResponseYou've already chosen the best response.0
What I mean is that if angle opposite 9 is theta, then cos of angle opposite 7 is sin theta
 one year ago

estudierBest ResponseYou've already chosen the best response.0
As JonasK had it at first...
 one year ago

estudierBest ResponseYou've already chosen the best response.0
expX, now eliminate theta....
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
you know i rely on wolf for this http://www.wolframalpha.com/input/?i=2*10*a+sin%28theta%29+%3D+10^2+%2B+a^2+++9^2%2C+2*10*a+cos%28theta%29+%3D+10^2+%2B+a^2+++7^2
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[32=20(a)\cos \theta+20(a)\sin \theta\]
 one year ago

estudierBest ResponseYou've already chosen the best response.0
Sin and Cos should auto response.....
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[\frac{ 32 }{ 20 a}=\cos \theta \sin \theta\]
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[\cos \theta \sin \theta =\sqrt{2} \sin(45\theta)\]
 one year ago

estudierBest ResponseYou've already chosen the best response.0
@Jonask An identity (well known) in Sin and Cos?
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
haa ... i was being fool trying to eliminate theta directly.
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
dw:1350210145598:dw
 one year ago

estudierBest ResponseYou've already chosen the best response.0
A bit messy but sufficient...:)
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
still quartic equation is pretty awful ... i must say!!
 one year ago

estudierBest ResponseYou've already chosen the best response.0
Yes, squaring and adding gets shot of theta...
 one year ago

estudierBest ResponseYou've already chosen the best response.0
U get after simplification...400x^2 = (x^2 +19)^2 + (x^2 +51)^2 > x^4 130 x^2 +1481
 one year ago

estudierBest ResponseYou've already chosen the best response.0
Which is quadratic in x^2
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
Oh .. that's pretty nice!!
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
let \[10^2a^2=b\] \[\frac{ (7^2 b)^2}{ (20a )^2}+\frac{ (9^2b)^2 }{ (20a)^2 }=1\]
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
dw:1350210434675:dw x+2y = 7 ..(1) y^2 + (x+y)^2 = 81 ..(2) hope that does it..
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
correction : x+2y = 10
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
solving shouldnt be much problem since from (1) , x+y = 10y and we plug that directly in (2)
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
the line with lenght 10 is not necessarily a diagonal when extrapolated ??
 one year ago

estudierBest ResponseYou've already chosen the best response.0
Eh? Some extra ssumptions there....
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
ohh..lol..so sorry! :P
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
can we eliminate according to triangle inequality 3,552 such that \[A=(10,834)^2\]
 one year ago

estudierBest ResponseYou've already chosen the best response.0
65 + 14 sqrt 14 I think.
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
same thing i just approaximated it
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[A=(\sqrt{64+14\sqrt{14}} )^2\]
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
@shubhamsrg if we consider the triangles to be equilateral then how wuld we solve it dw:1350178935156:dw with common side 10,
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
dw:1350179036162:dw such that the legth is now diagonal
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
you mean like this: dw:1350211506937:dw ??
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
for that i had given the solution above.. x+2y = 10 ..(1) y^2 + (x+y)^2 = 81 ..(2) from (1), x+y = 10y and we plug this in (2) to solve for y, and x and ultimately area..
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
nice work @sauravshakya
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
what disqualifies 6514root14
 one year ago

estudierBest ResponseYou've already chosen the best response.0
@Jonask That's for x^2, remember....
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
I think I have written reason for that too.
 one year ago

estudierBest ResponseYou've already chosen the best response.0
@sauravshakya Yes, good job (I think he just forgot it was for x^2)
 one year ago
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