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anonymous
 3 years ago
Area of square?
anonymous
 3 years ago
Area of square?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350208678915:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A square, a point inside of it distances from 3 vertices as shown

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This is for experimentX, who loves algebra..:)

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2haha ... you are kidding!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's not too hard..(it's still too early)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if we call ne side a then the area is \[A=a^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and the side is less than 17

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0according to triangle equality

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1350209046775:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[9^2=a^2+10^22(10)(a)\cos \theta\] \[762=10^2+a^22(a)(10)\cos (90\theta)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02 var 1 equation suggests simultaneous equations as the way to go....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i meant 7^2dw:1350176811646:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0JonasK is on the right track

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what about using the area rule

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2probably @hartnn method would work out too ... since they are all independent equations.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0"what about using the area rule" U just want to get rid of the 90 bit and then you can get rid of theta

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2still that's quite a bit of algebra since they are all non linear equations ... let's try something better.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Cos of angle opposite 7 is sin theta....

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1350209708034:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What I mean is that if angle opposite 9 is theta, then cos of angle opposite 7 is sin theta

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0As JonasK had it at first...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0expX, now eliminate theta....

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2you know i rely on wolf for this http://www.wolframalpha.com/input/?i=2*10*a+sin%28theta%29+%3D+10^2+%2B+a^2+++9^2%2C+2*10*a+cos%28theta%29+%3D+10^2+%2B+a^2+++7^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[32=20(a)\cos \theta+20(a)\sin \theta\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sin and Cos should auto response.....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 32 }{ 20 a}=\cos \theta \sin \theta\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\cos \theta \sin \theta =\sqrt{2} \sin(45\theta)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Jonask An identity (well known) in Sin and Cos?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2haa ... i was being fool trying to eliminate theta directly.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1350210145598:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A bit messy but sufficient...:)

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2still quartic equation is pretty awful ... i must say!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, squaring and adding gets shot of theta...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0U get after simplification...400x^2 = (x^2 +19)^2 + (x^2 +51)^2 > x^4 130 x^2 +1481

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Which is quadratic in x^2

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2Oh .. that's pretty nice!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let \[10^2a^2=b\] \[\frac{ (7^2 b)^2}{ (20a )^2}+\frac{ (9^2b)^2 }{ (20a)^2 }=1\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@estudier seems better

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350210434675:dw x+2y = 7 ..(1) y^2 + (x+y)^2 = 81 ..(2) hope that does it..

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0correction : x+2y = 10

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0solving shouldnt be much problem since from (1) , x+y = 10y and we plug that directly in (2)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the line with lenght 10 is not necessarily a diagonal when extrapolated ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Eh? Some extra ssumptions there....

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0ohh..lol..so sorry! :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[a=10,834, a=3,552\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can we eliminate according to triangle inequality 3,552 such that \[A=(10,834)^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.065 + 14 sqrt 14 I think.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0same thing i just approaximated it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[A=(\sqrt{64+14\sqrt{14}} )^2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@shubhamsrg if we consider the triangles to be equilateral then how wuld we solve it dw:1350178935156:dw with common side 10,

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1350179036162:dw such that the legth is now diagonal

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0you mean like this: dw:1350211506937:dw ??

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0for that i had given the solution above.. x+2y = 10 ..(1) y^2 + (x+y)^2 = 81 ..(2) from (1), x+y = 10y and we plug this in (2) to solve for y, and x and ultimately area..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nice work @sauravshakya

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what disqualifies 6514root14

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Jonask That's for x^2, remember....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think I have written reason for that too.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya Yes, good job (I think he just forgot it was for x^2)
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