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zaphod
 3 years ago
Help please :)
zaphod
 3 years ago
Help please :)

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zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0Show that the gain in potential energy of the block is approximately 0.01J?

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya @experimentX

rvgupta
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1350213222437:dw now subtract them and get the answer this difference is due to the increase in hight of second square due to being on its edge

rvgupta
 3 years ago
Best ResponseYou've already chosen the best response.1it is an approximation due to finding the height of the triangle

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0can u show the calculation?

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0how did u get mgh = 0.15?

rvgupta
 3 years ago
Best ResponseYou've already chosen the best response.1as m=150/1000 kg g=10 m/s^2 h=10/100 m multiply them and get the ans

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0wt bt the other one 0.16

rvgupta
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1350213752879:dw here h is slightly greater than the previous one thats why the ans will be 0.16 approx.

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0pythagoras....10^2 + 10^2 = x^2 x = 14.14

rvgupta
 3 years ago
Best ResponseYou've already chosen the best response.1right, but how will u get the solu.

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0thats what i posted this question..

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0how can the height be 11?

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0how did u get 11? i mean frm wt did u approximatre

rvgupta
 3 years ago
Best ResponseYou've already chosen the best response.1it was just to get the ans dude

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0hmm...do we actually consider the height from the horizontal to cntre of gravity or as a whole?

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0i dont knw how to solve it, coz the answer doesnt equal to 0.01 j, maybe theres a problem in the question. anyway thanks for helping

rvgupta
 3 years ago
Best ResponseYou've already chosen the best response.1were u talking about GPE or only about PE

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0gain in potential energy?

rvgupta
 3 years ago
Best ResponseYou've already chosen the best response.1i think the H should be taken from the cnt of gravity

VincentLyon.Fr
 3 years ago
Best ResponseYou've already chosen the best response.0Gain in potential energy is m g Δh , where Δh is gain in altitude of the centre of mass of the body.

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0yes :) so i got the answer as 0.03j not 0.01 can u chck where iwent wrong

VincentLyon.Fr
 3 years ago
Best ResponseYou've already chosen the best response.0Δh = 5√2  5 = 2.07 cm = 0.0207 m g = 9.81 m/s² m = 0.150 kg Hence gain = 0.03 J

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0i hve a second part in the question, cn i post it here..

zaphod
 3 years ago
Best ResponseYou've already chosen the best response.0The collision is perfectly elastic and, without sliding, the block turns about the corner as shown. The block is able to reach the position as shown in the image. 25% of the kinetic energy of the ball is transferred to the block. Calculate 1. the kinetic enrgy of the balll just before it strikes the block
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