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zaphod Group Title

Help please :)

  • 2 years ago
  • 2 years ago

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  1. zaphod Group Title
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    • 2 years ago
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  2. zaphod Group Title
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    Show that the gain in potential energy of the block is approximately 0.01J?

    • 2 years ago
  3. zaphod Group Title
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    @Coolsector

    • 2 years ago
  4. zaphod Group Title
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    @sauravshakya @experimentX

    • 2 years ago
  5. rvgupta Group Title
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    |dw:1350213222437:dw| now subtract them and get the answer this difference is due to the increase in hight of second square due to being on its edge

    • 2 years ago
  6. zaphod Group Title
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    why is it 0.16

    • 2 years ago
  7. rvgupta Group Title
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    it is an approximation due to finding the height of the triangle

    • 2 years ago
  8. zaphod Group Title
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    can u show the calculation?

    • 2 years ago
  9. zaphod Group Title
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    how did u get mgh = 0.15?

    • 2 years ago
  10. rvgupta Group Title
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    as m=150/1000 kg g=10 m/s^2 h=10/100 m multiply them and get the ans

    • 2 years ago
  11. zaphod Group Title
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    wt bt the other one 0.16

    • 2 years ago
  12. rvgupta Group Title
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    |dw:1350213752879:dw| here h is slightly greater than the previous one thats why the ans will be 0.16 approx.

    • 2 years ago
  13. zaphod Group Title
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    its 14.14 ? the height

    • 2 years ago
  14. rvgupta Group Title
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    how did u find the h

    • 2 years ago
  15. zaphod Group Title
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    pythagoras....10^2 + 10^2 = x^2 x = 14.14

    • 2 years ago
  16. rvgupta Group Title
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    right, but how will u get the solu.

    • 2 years ago
  17. zaphod Group Title
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    thats what i posted this question..

    • 2 years ago
  18. rvgupta Group Title
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    ok

    • 2 years ago
  19. zaphod Group Title
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    how can the height be 11?

    • 2 years ago
  20. rvgupta Group Title
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    it was an appro

    • 2 years ago
  21. zaphod Group Title
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    from 14?

    • 2 years ago
  22. rvgupta Group Title
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    was my method right

    • 2 years ago
  23. zaphod Group Title
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    how did u get 11? i mean frm wt did u approximatre

    • 2 years ago
  24. rvgupta Group Title
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    it was just to get the ans dude

    • 2 years ago
  25. zaphod Group Title
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    hmm...do we actually consider the height from the horizontal to cntre of gravity or as a whole?

    • 2 years ago
  26. rvgupta Group Title
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    can u give the solu

    • 2 years ago
  27. zaphod Group Title
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    i dont knw how to solve it, coz the answer doesnt equal to 0.01 j, maybe theres a problem in the question. anyway thanks for helping

    • 2 years ago
  28. rvgupta Group Title
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    were u talking about GPE or only about PE

    • 2 years ago
  29. zaphod Group Title
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    gain in potential energy?

    • 2 years ago
  30. rvgupta Group Title
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    i think the H should be taken from the cnt of gravity

    • 2 years ago
  31. zaphod Group Title
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    so its 5 cm

    • 2 years ago
  32. Vincent-Lyon.Fr Group Title
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    Gain in potential energy is m g Δh , where Δh is gain in altitude of the centre of mass of the body.

    • 2 years ago
  33. zaphod Group Title
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    yes :) so i got the answer as 0.03j not 0.01 can u chck where iwent wrong

    • 2 years ago
  34. Vincent-Lyon.Fr Group Title
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    Δh = 5√2 - 5 = 2.07 cm = 0.0207 m g = 9.81 m/s² m = 0.150 kg Hence gain = 0.03 J

    • 2 years ago
  35. zaphod Group Title
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    so i am right :)

    • 2 years ago
  36. Vincent-Lyon.Fr Group Title
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    You are!

    • 2 years ago
  37. zaphod Group Title
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    i hve a second part in the question, cn i post it here..

    • 2 years ago
  38. rvgupta Group Title
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    go ahead

    • 2 years ago
  39. zaphod Group Title
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    The collision is perfectly elastic and, without sliding, the block turns about the corner as shown. The block is able to reach the position as shown in the image. 25% of the kinetic energy of the ball is transferred to the block. Calculate 1. the kinetic enrgy of the balll just before it strikes the block

    • 2 years ago
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