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zaphod Group TitleBest ResponseYou've already chosen the best response.0
Show that the gain in potential energy of the block is approximately 0.01J?
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
@Coolsector
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya @experimentX
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
dw:1350213222437:dw now subtract them and get the answer this difference is due to the increase in hight of second square due to being on its edge
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
why is it 0.16
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
it is an approximation due to finding the height of the triangle
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
can u show the calculation?
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
how did u get mgh = 0.15?
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
as m=150/1000 kg g=10 m/s^2 h=10/100 m multiply them and get the ans
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
wt bt the other one 0.16
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
dw:1350213752879:dw here h is slightly greater than the previous one thats why the ans will be 0.16 approx.
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
its 14.14 ? the height
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
how did u find the h
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
pythagoras....10^2 + 10^2 = x^2 x = 14.14
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
right, but how will u get the solu.
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
thats what i posted this question..
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
how can the height be 11?
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
it was an appro
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
was my method right
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
how did u get 11? i mean frm wt did u approximatre
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
it was just to get the ans dude
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
hmm...do we actually consider the height from the horizontal to cntre of gravity or as a whole?
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
can u give the solu
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i dont knw how to solve it, coz the answer doesnt equal to 0.01 j, maybe theres a problem in the question. anyway thanks for helping
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
were u talking about GPE or only about PE
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
gain in potential energy?
 one year ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
i think the H should be taken from the cnt of gravity
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
so its 5 cm
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Gain in potential energy is m g Δh , where Δh is gain in altitude of the centre of mass of the body.
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
yes :) so i got the answer as 0.03j not 0.01 can u chck where iwent wrong
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Δh = 5√2  5 = 2.07 cm = 0.0207 m g = 9.81 m/s² m = 0.150 kg Hence gain = 0.03 J
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
so i am right :)
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
You are!
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i hve a second part in the question, cn i post it here..
 one year ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
The collision is perfectly elastic and, without sliding, the block turns about the corner as shown. The block is able to reach the position as shown in the image. 25% of the kinetic energy of the ball is transferred to the block. Calculate 1. the kinetic enrgy of the balll just before it strikes the block
 one year ago
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