Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

zaphod Group TitleBest ResponseYou've already chosen the best response.0
Show that the gain in potential energy of the block is approximately 0.01J?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya @experimentX
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
dw:1350213222437:dw now subtract them and get the answer this difference is due to the increase in hight of second square due to being on its edge
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
why is it 0.16
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
it is an approximation due to finding the height of the triangle
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
can u show the calculation?
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
how did u get mgh = 0.15?
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
as m=150/1000 kg g=10 m/s^2 h=10/100 m multiply them and get the ans
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
wt bt the other one 0.16
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
dw:1350213752879:dw here h is slightly greater than the previous one thats why the ans will be 0.16 approx.
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
its 14.14 ? the height
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
how did u find the h
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
pythagoras....10^2 + 10^2 = x^2 x = 14.14
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
right, but how will u get the solu.
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
thats what i posted this question..
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
how can the height be 11?
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
it was an appro
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
was my method right
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
how did u get 11? i mean frm wt did u approximatre
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
it was just to get the ans dude
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
hmm...do we actually consider the height from the horizontal to cntre of gravity or as a whole?
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
can u give the solu
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i dont knw how to solve it, coz the answer doesnt equal to 0.01 j, maybe theres a problem in the question. anyway thanks for helping
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
were u talking about GPE or only about PE
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
gain in potential energy?
 2 years ago

rvgupta Group TitleBest ResponseYou've already chosen the best response.1
i think the H should be taken from the cnt of gravity
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Gain in potential energy is m g Δh , where Δh is gain in altitude of the centre of mass of the body.
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
yes :) so i got the answer as 0.03j not 0.01 can u chck where iwent wrong
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
Δh = 5√2  5 = 2.07 cm = 0.0207 m g = 9.81 m/s² m = 0.150 kg Hence gain = 0.03 J
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
so i am right :)
 2 years ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
You are!
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
i hve a second part in the question, cn i post it here..
 2 years ago

zaphod Group TitleBest ResponseYou've already chosen the best response.0
The collision is perfectly elastic and, without sliding, the block turns about the corner as shown. The block is able to reach the position as shown in the image. 25% of the kinetic energy of the ball is transferred to the block. Calculate 1. the kinetic enrgy of the balll just before it strikes the block
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.