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frx

  • 3 years ago

Can someone show me way \[\sqrt{(1-6i)^{2}+4(7+9i)} = 3+4i\]

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  1. frx
    • 3 years ago
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    why*

  2. Rimplestorck
    • 3 years ago
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    you could maybe square both sides? does it work?

  3. frx
    • 3 years ago
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    Well, I don't have the answer 3+4i from the beginning so that wouldn't work

  4. frx
    • 3 years ago
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    @mukushla could you please check this out?

  5. mukushla
    • 3 years ago
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    simplify under radical first

  6. frx
    • 3 years ago
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    \[\sqrt{(-35-12i)+(28+36i)}\]

  7. frx
    • 3 years ago
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    ?

  8. mukushla
    • 3 years ago
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    yes right and..simplify further

  9. frx
    • 3 years ago
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    \[\sqrt{-7+24i}\]

  10. mukushla
    • 3 years ago
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    now see this ... very complete article about taking square root of a complex number

  11. frx
    • 3 years ago
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    Ok, thanks :)

  12. mukushla
    • 3 years ago
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    no problem

  13. frx
    • 3 years ago
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    That pdf was really great, can't thank you enough! :D

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