## frx Group Title Draw the set S of complex numbers such that $|z-2i|<2,,, \Im (z)=1$ What is the argument when $z \in S$ one year ago one year ago

1. frx Group Title

$|a-i|<2$

2. frx Group Title

But what does that say on a graph?

3. frx Group Title

-2<a-i<2

4. experimentX Group Title

says it lines in the region inside a circle with radius 2 and center 0,2

5. frx Group Title
6. frx Group Title

It's no circle?

7. frx Group Title

Is it because the Im(z) is constant at 1 and -2< Re(z) < 2, so it just varies in the Re(z) plane?

8. experimentX Group Title

so you want z such that it's imaginary part is constant?

9. frx Group Title

No i think I'm a bit wrong in my thoughts

10. experimentX Group Title

put z = x + i in that equation |x + i - 2i| < 2 x^2 + 1^2 < 4 x^2 < 3 |x| < sqrt(3) -3 < x < 3

11. frx Group Title

Is it not Re betweem -2 and 2 ?

12. experimentX Group Title

sorry ... sqrt(3) .. lol

13. frx Group Title

Ah, okey :) So how do I get the argument from that?

14. frx Group Title

Just to try -sqrt3-i and sqrt3-i ?

15. frx Group Title

But they are not included in the interval so instead should i take some random x value inside the interval?

16. experimentX Group Title

yeah you can get that ... |x| must be sqrt(3)'s ...just put it up and see what you get.

17. frx Group Title

So i should use -i as Im, right?

18. frx Group Title

If so the argument is $\frac{ 11\pi }{ 6 }$

19. experimentX Group Title

put z = x + i in that equation |x + i - 2i| < 2 x^2 + 1^2 < 4 x^2 < 3 |x| < sqrt(3) -sqrt(3) < x < sqrt(3) put z = x + 11pi/6 i <--- in above

20. frx Group Title

$z=x+\frac{ 11\pi }{6 }i,$ where $-\sqrt{3}<x<\sqrt{3}$

21. frx Group Title

Is that what you meant?

22. experimentX Group Title

no ... find the value of x in similar fashion

23. frx Group Title

Sorry but i have to go for now. But thank you for your help and patience, will look back at this later.