Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

frx Group Title

Draw the set S of complex numbers such that \[|z-2i|<2,,, \Im (z)=1\] What is the argument when \[z \in S\]

  • one year ago
  • one year ago

  • This Question is Closed
  1. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[|a-i|<2\]

    • one year ago
  2. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    But what does that say on a graph?

    • one year ago
  3. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    -2<a-i<2

    • one year ago
  4. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    says it lines in the region inside a circle with radius 2 and center 0,2

    • one year ago
  5. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    http://www.wolframalpha.com/input/?i=|a-i|%3C2

    • one year ago
  6. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    It's no circle?

    • one year ago
  7. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Is it because the Im(z) is constant at 1 and -2< Re(z) < 2, so it just varies in the Re(z) plane?

    • one year ago
  8. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so you want z such that it's imaginary part is constant?

    • one year ago
  9. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    No i think I'm a bit wrong in my thoughts

    • one year ago
  10. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    put z = x + i in that equation |x + i - 2i| < 2 x^2 + 1^2 < 4 x^2 < 3 |x| < sqrt(3) -3 < x < 3

    • one year ago
  11. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Is it not Re betweem -2 and 2 ?

    • one year ago
  12. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry ... sqrt(3) .. lol

    • one year ago
  13. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Ah, okey :) So how do I get the argument from that?

    • one year ago
  14. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Just to try -sqrt3-i and sqrt3-i ?

    • one year ago
  15. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    But they are not included in the interval so instead should i take some random x value inside the interval?

    • one year ago
  16. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah you can get that ... |x| must be sqrt(3)'s ...just put it up and see what you get.

    • one year ago
  17. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    So i should use -i as Im, right?

    • one year ago
  18. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    If so the argument is \[\frac{ 11\pi }{ 6 }\]

    • one year ago
  19. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    put z = x + i in that equation |x + i - 2i| < 2 x^2 + 1^2 < 4 x^2 < 3 |x| < sqrt(3) -sqrt(3) < x < sqrt(3) put z = x + 11pi/6 i <--- in above

    • one year ago
  20. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[z=x+\frac{ 11\pi }{6 }i, \] where \[-\sqrt{3}<x<\sqrt{3}\]

    • one year ago
  21. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Is that what you meant?

    • one year ago
  22. experimentX Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    no ... find the value of x in similar fashion

    • one year ago
  23. frx Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Sorry but i have to go for now. But thank you for your help and patience, will look back at this later.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.