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frx
Group Title
Draw the set S of complex numbers such that
\[z2i<2,,, \Im (z)=1\]
What is the argument when \[z \in S\]
 one year ago
 one year ago
frx Group Title
Draw the set S of complex numbers such that \[z2i<2,,, \Im (z)=1\] What is the argument when \[z \in S\]
 one year ago
 one year ago

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frx Group TitleBest ResponseYou've already chosen the best response.0
But what does that say on a graph?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
says it lines in the region inside a circle with radius 2 and center 0,2
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=ai%3C2
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
It's no circle?
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Is it because the Im(z) is constant at 1 and 2< Re(z) < 2, so it just varies in the Re(z) plane?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
so you want z such that it's imaginary part is constant?
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
No i think I'm a bit wrong in my thoughts
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
put z = x + i in that equation x + i  2i < 2 x^2 + 1^2 < 4 x^2 < 3 x < sqrt(3) 3 < x < 3
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Is it not Re betweem 2 and 2 ?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
sorry ... sqrt(3) .. lol
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Ah, okey :) So how do I get the argument from that?
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Just to try sqrt3i and sqrt3i ?
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
But they are not included in the interval so instead should i take some random x value inside the interval?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
yeah you can get that ... x must be sqrt(3)'s ...just put it up and see what you get.
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
So i should use i as Im, right?
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
If so the argument is \[\frac{ 11\pi }{ 6 }\]
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
put z = x + i in that equation x + i  2i < 2 x^2 + 1^2 < 4 x^2 < 3 x < sqrt(3) sqrt(3) < x < sqrt(3) put z = x + 11pi/6 i < in above
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
\[z=x+\frac{ 11\pi }{6 }i, \] where \[\sqrt{3}<x<\sqrt{3}\]
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Is that what you meant?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
no ... find the value of x in similar fashion
 one year ago

frx Group TitleBest ResponseYou've already chosen the best response.0
Sorry but i have to go for now. But thank you for your help and patience, will look back at this later.
 one year ago
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