suppose the lateral area of a right circular cone and the area of a sphere is equal 64π inches^2. if the radius of the sphere and the radius of the base of the cone are equal, what is the volume of the cone?

- anonymous

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- anonymous

Is the question complete..? :D

- anonymous

Sorry! the question is now complete please help me :( thanks!

- anonymous

|dw:1350220886630:dw|

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## More answers

- anonymous

i really don't know how it looks like,but i guess what you did was right. :)

- anonymous

how can I find the total area and volume?:(

- experimentX

what's the prism ? what's pyramid? make your figure properly ... this shouldn't be difficult.

- experimentX

|dw:1350221237912:dw|

- anonymous

regular hexagonal prism with 10-in long sides and apothem of length 9-in long. uhh, yeah! I think so.

- experimentX

|dw:1350221347921:dw|
|dw:1350221367792:dw|

- anonymous

|dw:1350221334283:dw|

- anonymous

miyuri what is 12 there?

- anonymous

experimentX yeah but how can i find the volume and total area?

- anonymous

It would be essential in finding the volume...

- anonymous

To find the total area multiply the area of triangle by 6 + area of hexagon..

- experimentX

volume of pyramid = 1/3* area of hexagon * height

- experimentX

for surface area ... |dw:1350221785183:dw|

- experimentX

|dw:1350221947122:dw|

- anonymous

Total area = \[(\frac{15*10}{2}*6)+(\frac{10*9}{2}*6)\]

- experimentX

yeah ... looks like that's correct!!

- anonymous

Gee! thanks a lot!!!!! but how is this? find the volume of the region outside the pyramid and inside the prism.

- experimentX

find the volume of pyramid ...
find the volume of prism ...
subtract 1 from 2

- anonymous

Volume = \[(\frac{10*9}{2}*6)*\frac{1}{3}*12 - (\frac{10*9}{2}*6*12)\]

- experimentX

lol ... you did the opposite? is height 12??

- anonymous

I took the height of the pyramid...

- experimentX

should be something like this if 12 is height
\[ - (\frac{10*9}{2}*6)*\frac{1}{3}*12 + (\frac{10*9}{2}*6*12) \]

- anonymous

Oops yeah @experimentX I changed the sides of the equation... :D

- experimentX

well ...i guess that it is!!

- anonymous

so 4320 is the volume?=)

- anonymous

What is the area of the base and the height?

- anonymous

Yeah @gandako U are correct.. volume=4320

- anonymous

I found the height from the triangle drawn above.. x=12

- anonymous

but how about the are of the base @Miyuru ?

- anonymous

Base = side of the hexagon

- anonymous

i can't understand:(

- anonymous

From which step are you confused?

- anonymous

here: volume of pyramid=1/3 * area of the base *height how can get the are of the base?

- anonymous

Here the base is the hexagon and it's area is six times the area of a triangle...

- anonymous

6 x bh/2 is this? what is the value of b in there?

- anonymous

b = 10

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